jason

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visits member for 2 years, 3 months
seen May 3 '12 at 9:57

Feb
13
awarded  Popular Question
May
3
accepted Stirling Numbers of the Second Kind (deriving S(m, m - 2))
May
3
comment Stirling Numbers of the Second Kind (deriving S(m, m - 2))
Thanks for that, dividing by 2 gave me your expected result. I checked this with a few test numbers and it seems like the book made a mistake. :)
May
3
comment Stirling Numbers of the Second Kind (deriving S(m, m - 2))
The book defined Stirling numbers of the second kind as: S(m, n) = 1/n! * sum(k=0 to n)[((-1)^k) * $\dbinom{n}{n-k}$(n - k)^m] Sorry about the formatting of it, I'm not really familiar with LaTeX
May
3
asked Stirling Numbers of the Second Kind (deriving S(m, m - 2))
Apr
25
accepted Combinations with Repetition, bounded above and by a subset
Apr
24
revised Combinations with Repetition, bounded above and by a subset
fixed spelling mistake
Apr
24
asked Combinations with Repetition, bounded above and by a subset
Apr
24
awarded  Scholar
Apr
24
accepted 20 books 5 different shelves
Apr
24
comment 20 books 5 different shelves
Ahh, that clears it up. Thanks a lot :) Is there a way to mark your answer is the correct one? Sorry, I'm new here. Edit: Found it
Apr
24
comment 20 books 5 different shelves
Thanks for the reply, I was wondering if you could clarify the first part where you say there are 15^6 ways to place the books. I guess I'm having a mind blank, because I can't really see how you got there. Once one book is put onto a shelf, the remaining books decrease so I thought this would lead to a factorial of some kind. Thanks
Apr
24
awarded  Student
Apr
24
asked 20 books 5 different shelves