279 reputation
413
bio website twitter.com/ajax333221
location Mexico
age 24
visits member for 2 years, 6 months
seen Oct 4 at 3:23

Sep
23
awarded  Popular Question
May
13
awarded  Caucus
Dec
6
comment What are the odds of cracking a cellphone pattern-lock?
@BillDubuque I agree, after knowing the total combinations should not be hard to calculate the odds of cracking one of those
Dec
6
comment What are the odds of cracking a cellphone pattern-lock?
@sacohe the minimum is connecting 2 dots, the maximum however, was left blank because the answers I want to be like a function that you put one number here and then everything is done using that number sorry my englishç
Dec
6
asked What are the odds of cracking a cellphone pattern-lock?
Sep
8
accepted How to calculate a fullhouse after dealing 5 cards?
Sep
8
awarded  Citizen Patrol
Sep
8
revised How to calculate a fullhouse after dealing 5 cards?
deleted 77 characters in body
Sep
8
revised How to calculate a fullhouse after dealing 5 cards?
added 81 characters in body
Sep
8
asked How to calculate a fullhouse after dealing 5 cards?
Aug
31
awarded  Autobiographer
Jul
14
accepted The probabilty of a new arrangement of 52 cards deck?
Jul
14
revised Formula to get total combination possibilities
edited body
Jul
14
asked The probabilty of a new arrangement of 52 cards deck?
Jun
9
comment The Monty Hall problem
however, because this problem gained that much popularity, I will guess they will only give you that option when you chose the car in the first place, thus, you should not change
Jun
8
comment Most Probable Sum
if someone told me "hey, lets roll a die until it reaches 101 or more. If it is 101 or 102 I win, if it is 103-106 you win" I would instantly agree and more likely to lose
Jun
8
revised I can't find differences between $P(1+r)^n$ and $P(2.71828)^{rn}$
added 16 characters in body
Jun
8
comment I can't find differences between $P(1+r)^n$ and $P(2.71828)^{rn}$
@Henry maybe because I translated that part wrong, I should have included the word "rate"
Jun
8
accepted I can't find differences between $P(1+r)^n$ and $P(2.71828)^{rn}$
Jun
8
asked I can't find differences between $P(1+r)^n$ and $P(2.71828)^{rn}$