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seen Oct 27 '12 at 16:39
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Apr
23
awarded  Yearling
Sep
6
comment Inequality. $ab^2+bc^2+ca^2 \geq a+b+c.$
Iuli's proof is substantially correct and you can prove the second displayed equation using rearrangements. This method doesn't necessarily have to prove symmetric inequalities. You just have to take the correct permutation to get $y^2z+z^2x+x^2y$. For instance, supposing that $y\geq x\geq z$, the same inequality can be proved.
Sep
5
revised Inequality. $ab^2+bc^2+ca^2 \geq a+b+c.$
Typo in the exponent of the first displayed equation. Typo in second equation. Removed the rest, now useless.
Sep
5
suggested suggested edit on Inequality. $ab^2+bc^2+ca^2 \geq a+b+c.$
Aug
28
awarded  Good Answer
Aug
14
comment Primes Not Dividing $\binom{2n}{n}$
Any such prime appears exactly twice both in the numerator and the denominator of $\binom{2n}{n}= \frac{(2n)!}{(n!)^2}$.
Jun
8
awarded  Constituent
Jun
8
awarded  Caucus
Jun
1
comment How to show that if $x_1,\ldots,x_n$ are real numbers, then $|x_1|\ldots|x_n| \le |x_1|^2 + \cdots + |x_n|^2$
The right kind of such inequalities should be homogeneous of the same degree on both sides. Here, it is homogeneous of degree $n$ on the left and $2$ on the right.
May
14
comment Exercise: continuity of a function of two variables
Hint: Use uniform continuity of $\phi$ on compact sets.
May
12
answered UPDATE: How to find the order of elliptic curve over finite field extension
May
11
awarded  Editor
May
11
revised Cyclic Group Questions
added 16 characters in body
May
11
comment Cyclic Group Questions
You're right, I forgot when there are no $2$'s at all. I will edit the answer. Thanks!
May
11
answered Cyclic Group Questions
May
10
comment calculating the amplitude of a cosine function
Why the notation $\| A \|$ etc. in the first displayed formula?
May
10
comment When did Fubini's name get applied to the theorem without measures?
Look at the wikipedia entry for Fubini's theorem. I will just add that in Italian universities, the theorem is known as the theorem of Fubini-Tonelli (and pay attention to the spelling, one 'n').
May
10
awarded  Supporter
May
5
answered The power series $\sum\limits_{n=1}^{\infty} \frac {z^{n} }{ n^{2}} \ $
May
2
comment Importance of rigor
It is Littlewood, not Landau, who proved that $\mathrm{li}(x) - \pi(x)$ changes sign infinitely often. The first one to give an upper bound on the range of $x$ when this first happens is Skewes.