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Mar
11
comment Prove $(1 +\frac{ 1}{n}) ^ {n} \ge 2$
Nope. This is a direct proof using binomial expansion.
Mar
11
answered Prove $(1 +\frac{ 1}{n}) ^ {n} \ge 2$
Mar
6
comment Show that if $n$ is composite, then $\phi(n) \leq n-\sqrt{n}$
math.stackexchange.com/questions/896920/…
Mar
4
revised Find all solutions to $x^{10} = 1 \pmod {377}$
minor corrections
Mar
4
suggested approved edit on Find all solutions to $x^{10} = 1 \pmod {377}$
Mar
2
revised Prove that there is an increasing sequence $\{a_n\}$ of points in $A$ such that $\lim a_n = \sup A$.
minor correction
Mar
2
suggested approved edit on Prove that there is an increasing sequence $\{a_n\}$ of points in $A$ such that $\lim a_n = \sup A$.
Feb
14
suggested rejected edit on Schwarz Inequality?
Feb
14
answered Divide By Vector
Feb
13
answered Evaluating $\lim_{n\to\infty}\small\left(\frac{1}{\sqrt{n}\sqrt{n+1}}+\frac{1}{\sqrt{n}\sqrt{n+2}}+\cdots+\frac{1}{\sqrt{n}\sqrt{n+n}}\right)$
Jan
29
revised Find $\lim_{x\to \infty}{[({1\over e}(1+{1\over x})^x)]^x}$.
corrected the latex
Jan
29
suggested approved edit on Find $\lim_{x\to \infty}{[({1\over e}(1+{1\over x})^x)]^x}$.
Jan
21
comment show that $ 4 = \sum_{n=1}^\infty (-2)^{n+1}\frac{n+2}{n!} $
@learnmore 2*(-1)^n is not (-2)^n
Jan
20
comment Does $\int_0^\infty \sin(x^{2/3}) dx$ converges?
$x = y^{3/2}$ then $dx = \frac{3}{2}y^{1/2}dy$
Jan
14
comment Showing $d(x,y) = \frac{|x-y|}{1+|x-y|}$ is a distance.
math.stackexchange.com/questions/686792/…
Dec
19
awarded  Constituent
Dec
8
awarded  Caucus
Dec
6
answered How to prove that $A^2$ is a symmetric matrix
Dec
2
comment Computing eigenvector corresponding to dominant eigenvector.
en.wikipedia.org/wiki/Power_iteration
Nov
26
comment How to prove $n < \left(1+\frac{1}{\sqrt{n}}\right)^n$
You can lower that limit of 144 even further. Note that $$ 1 + \sqrt{n} + \dfrac{(n-1)}2 + \dfrac{n(n-1)(n-2)}{6} \dfrac1{n^{3/2}} = \frac{n^{3/2}}{6} + \frac{n}{2} + \frac{n^{1/2}}{2} + \frac{1}{3n^{1/2}} + \frac{1}{2}$$. The RHS is greater than (using the first three terms) $$\frac{n}{2} + \frac{n^{1/2}(n + 3)}{6}$$. It is quite easy to show that $$\frac{n^{1/2}(n + 3)}{6} > \frac{n}{2}$$. This gives you the result, without needing calculus or computing for particular values.