1,615 reputation
411
bio website cse.iitb.ac.in/~aruniyer
location India
age 30
visits member for 2 years, 6 months
seen 50 mins ago

Mar
31
comment Using SVD in PCA for image compression
You seem to be confusing scaling with compression. If you just want to reduce the dimensions, then just downscale your images. en.wikipedia.org/wiki/Image_scaling
Mar
28
answered How to realize $\lambda_{max}(X)$ is convex?
Mar
28
answered What is the distribution of the dot product of a Dirichlet vector with a fixed vector?
Mar
27
comment Set of vectors linearly independent
Note that $u_i = v_i - v_{i - 1}$ for $i > 1$
Mar
27
comment finding the unspecified ${\bf E}[X]$ and $\rm var(X)$ given the expectation of higher powers of $X$
A standard normal random variable has mean 0 and variance 1.
Dec
31
comment Relation between convex set and convex function
$\phi(\lambda x + (1 - \lambda)y)=\inf_{a\in A}\|\lambda x + (1 - \lambda)y-a\|$. Think of how you can play around with RHS. Note that, $\lambda a + (1 - \lambda) a = a$.
Dec
3
comment Proving by induction that $1+\frac{1}{2}+\frac{1}{3}+…+\frac{1}{n}\le\frac{n}{2}+1$ holds for all $n \ge 1$
?? Haven't they simply added 1/n+1 to both sides of the hypothesis statement. Why is it so magical to you?
Nov
24
comment $ \begin{bmatrix} -2 & 5 & 4 \\-1 & 0 & 0 \\0 & 4 & 3 \end{bmatrix}^{2013}$ =?
Sure, give me sometime and I will actually do it and write it up. Do you want me to? My point that it was doable precisely because it is a special matrix.
Nov
24
answered $ \begin{bmatrix} -2 & 5 & 4 \\-1 & 0 & 0 \\0 & 4 & 3 \end{bmatrix}^{2013}$ =?
Sep
15
answered Finding the equation of a circle ?
Sep
10
comment Support of a vector
support of a vector is the number of non-zero elements in that vector.
Sep
6
comment What is the difference between commutatitivity and distributivity?
No, nothing to add. Hurkyl (+1), pretty much has said everything I wanted to convey.
Sep
6
comment What is the difference between commutatitivity and distributivity?
Do you understand my question? Given two operators A and B, AB = A(B(x)). Unless B's range is A's domain, A(B(x)) does not make sense. Similarly, BA = B(A(x)) therefore, A's range has to be B's domain. Finally, for AB = BA to be true, A's range has to be same as B's range. Thereby, unless you define A and B's domain and range, you cannot talk about commutativity. That is why, I asked you, please write the domain and range of the two operators that you speak. Then we can think about commutativity.
Sep
6
comment What is the difference between commutatitivity and distributivity?
Please define the domain and range of your operators A and $\sum$. Without that, talking about commutativity is pointless.
Aug
30
revised Prove that the CDF of a random variable is always right-continuous
fixing some braces
Aug
30
suggested suggested edit on Prove that the CDF of a random variable is always right-continuous
Aug
30
revised is $\{(x,y) : x,y \in \mathbb{Z} \}$ a closed set?
Just using prettier norm notation :-)
Aug
30
suggested suggested edit on is $\{(x,y) : x,y \in \mathbb{Z} \}$ a closed set?
Aug
27
comment Counting Question
Choose the even number first, then select the other numbers.
Aug
27
comment Reproducing Kernel Hilbert Spaces for Dummies
That's pretty much what it seems to be if I read that paragraph in the paper correctly.