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visits member for 2 years, 4 months
seen Jul 25 at 2:48

Ross alumnus interested in number theory, combinatorics, and elliptic curves.


May
6
answered Derivative of $e^{-x}$
Apr
30
comment Rubik's cube puzzle
Could we cut the Rubik's cube in such a way that the cross-section is in the shape of a hexagon?
Apr
30
answered I want a clear explanation for the Principle of Strong Mathematical Induction
Apr
27
revised Best self study math books?
Grammar was cleaned up.
Apr
27
suggested suggested edit on Best self study math books?
Apr
27
answered Best self study math books?
Apr
27
comment Combinatorial Mystery Function
I was confused at first about the notation, so I sat down and tried again and got $\frac{(e_1+e_2+...+e_n -1)!}{e_1!e_2!...e_n!}$. Which I'm guessing is the same as your result. Thanks!
Apr
27
accepted Combinatorial Mystery Function
Apr
26
comment Showing that $f_{2n+1}=f_{n+1}^2+f_n^2$.
There is actually an interesting article about this interpretation of the Fibonacci sequence in this month's Mathematics Magazine for those who are curious about some more of its utility in proofs.
Apr
26
awarded  Editor
Apr
26
comment Combinatorial Mystery Function
Thanks! I fixed the abusive notation.
Apr
26
revised Combinatorial Mystery Function
Made notation less abusive.
Apr
25
answered Showing that $f_{2n+1}=f_{n+1}^2+f_n^2$.
Apr
25
awarded  Scholar
Apr
25
accepted Non-linear Recursion
Apr
25
awarded  Supporter
Apr
25
comment Show that $ a,b, \sqrt{a}+ \sqrt{b} \in\mathbb Q \implies \sqrt{a},\sqrt{b} \in\mathbb Q $
Sorry, I didn't read the part about not being computational. Also, this just boils down to Bill Dubuque's proof.
Apr
25
answered Show that $ a,b, \sqrt{a}+ \sqrt{b} \in\mathbb Q \implies \sqrt{a},\sqrt{b} \in\mathbb Q $
Apr
25
awarded  Teacher
Apr
25
answered Direct Proof that $1 + 3 + 5 + \cdots+ (2n - 1) = n\cdot n$