Zhou Heng
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 Mar16 answered Ask for a question about independence Mar6 accepted Ask for a thing about multivariable concave function Mar6 comment Ask for a thing about multivariable concave function Great! So, is sufficiently smooth concave function a special case of Lipschitz continuous function? Mar6 revised Ask for a thing about multivariable concave function added 22 characters in body Mar6 comment Ask for a thing about multivariable concave function I see the mistake in the post. I should add "absolute value of" Mar6 comment Ask for a thing about multivariable concave function why $M$ does not exist for $-x^2$? It is a convex function and the slope of the tangent line on the parabola satisfies the inequality for the fixed $x_0$ and all other $x$. Mar6 comment Ask for a thing about multivariable concave function why not M=1? you know what I mean. And, if we take M=17, the inequality does not hold for all x. Mar6 asked Ask for a thing about multivariable concave function Mar4 accepted Expression for the size of type class, or multinomial coefficient. Mar3 answered Expression for the size of type class, or multinomial coefficient. Mar2 comment Expression for the size of type class, or multinomial coefficient. It seems that we can use Stirling's approximation $n!\approx\sqrt{2\pi n}(n/e)^n$. But this is only an approximation and a big-O term $O(\ldots(n))$ or something is needed for the equation to hold exactly. I don't know what form of $O(\ldots(n))$ is. Any comment is welcome! ... I have to go to bed now:-( Mar2 asked Expression for the size of type class, or multinomial coefficient. Feb21 accepted An optimization problem with regard to permutation function Feb21 comment An optimization problem with regard to permutation function I got it. Thank you! (I mean the former) Feb21 asked An optimization problem with regard to permutation function Feb17 comment Ask for a question about independence @Did: so the independence of $X'$ and $(X,Y)$ can not be derived from the independence of $X$ and $X'$? Note that $Y$ is generated solely from $X$, not like $Y=X+X'$ in the answer where $Y$ is also determined by $X'$. Feb17 comment Ask for a question about independence Yes, I must have omitted some assumptions, but I don't know what they are. Currently the assumptions can be summarized as: $X$ and $X'$ are iid with common probability $p(x)$. $Y$ is generated from $X$ according to the trasition probability $p(y|x)$ (sorry for the typo in the original post; I have corrected it). I really can not think of any other assumptions. Maybe someone who read the proof of Shannon's channel coding theorem before and familiar with random coding and joint typicality can answer this question. Feb17 revised Ask for a question about independence edited body Feb17 comment Ask for a question about independence but $X'$ and $Y$ are indeed independent in the proof to show subsequent results. Let's assume $X'$ and $X$ have the same distribution. Feb17 asked Ask for a question about independence