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awarded  Nice Question
2d
comment Convolution form of the renewal density
@Math1000: honestly, I didn't understand either of your two steps. But I think that's more about my not understanding basics of convolutions. If someone wants to chime in and verify, then I'll be glad to accept and then work through it myself later...
Apr
20
awarded  Yearling
Mar
23
awarded  Promoter
Mar
22
revised Sparsity conditions for a Normal hypothesis testing problem
added references to specific pages, etc.
Mar
21
comment Asymptotically unbiased estimator for 1/p in Bernouilli distribution?
Isn't your estimator asymptotically unbiased just by continuous mapping? And since $\omega_n$ is fixed, then it shouldn't matter in the limit since the probability that it occurs goes to zero as you mentioned.
Mar
21
asked Sparsity conditions for a Normal hypothesis testing problem
Mar
6
revised Pointwise convergence from $\liminf$ inequality and convergence of sums
added 110 characters in body; edited tags; edited title
Mar
6
comment Pointwise convergence from $\liminf$ inequality and convergence of sums
@FriedrichPhilipp: OK. Thanks, my bad. The example in the paper is not really integration with respect to Lebesgue measure. Sorry to lead you astray there. I've edited.
Mar
6
asked Pointwise convergence from $\liminf$ inequality and convergence of sums
Feb
26
comment The integral $\int f \mu(dt)$ versus $\int f \mu(t) dt$
@Did: ah, I see. So I suppose that if you can solve $\int \alpha e^{-\alpha t} \mu(t) dt = 1$ and such an $\alpha$ exists, then $\mu(t) \ll e^{\alpha t}$ must hold. gotcha.
Feb
26
comment The integral $\int f \mu(dt)$ versus $\int f \mu(t) dt$
@Did: after checking the details again, does this technically require us to assume that $\mu(t) < \infty$? not unreasonable I suppose.
Feb
26
comment The integral $\int f \mu(dt)$ versus $\int f \mu(t) dt$
@Did: wow. that probably seemed completely obvious to you, but I never would've seen it this way. much appreciated.
Feb
26
comment The integral $\int f \mu(dt)$ versus $\int f \mu(t) dt$
@echzhen yes. but my actual question goes a little beyond that. sorry, I've edited to make this clearer.
Feb
26
revised The integral $\int f \mu(dt)$ versus $\int f \mu(t) dt$
changed the question to make it more pointed
Feb
26
revised The integral $\int f \mu(dt)$ versus $\int f \mu(t) dt$
added 5 characters in body
Feb
26
revised The integral $\int f \mu(dt)$ versus $\int f \mu(t) dt$
added 55 characters in body
Feb
26
asked The integral $\int f \mu(dt)$ versus $\int f \mu(t) dt$
Feb
21
revised Intuition behind the renewal equation
updated my understanding of the renewal measure...
Feb
21
revised Upcrossings of the forward recurrence time
deleted 44 characters in body