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 1d awarded Nice Question 2d comment Convolution form of the renewal density @Math1000: honestly, I didn't understand either of your two steps. But I think that's more about my not understanding basics of convolutions. If someone wants to chime in and verify, then I'll be glad to accept and then work through it myself later... Apr 20 awarded Yearling Mar 23 awarded Promoter Mar 22 revised Sparsity conditions for a Normal hypothesis testing problem added references to specific pages, etc. Mar 21 comment Asymptotically unbiased estimator for 1/p in Bernouilli distribution? Isn't your estimator asymptotically unbiased just by continuous mapping? And since $\omega_n$ is fixed, then it shouldn't matter in the limit since the probability that it occurs goes to zero as you mentioned. Mar 21 asked Sparsity conditions for a Normal hypothesis testing problem Mar 6 revised Pointwise convergence from $\liminf$ inequality and convergence of sums added 110 characters in body; edited tags; edited title Mar 6 comment Pointwise convergence from $\liminf$ inequality and convergence of sums @FriedrichPhilipp: OK. Thanks, my bad. The example in the paper is not really integration with respect to Lebesgue measure. Sorry to lead you astray there. I've edited. Mar 6 asked Pointwise convergence from $\liminf$ inequality and convergence of sums Feb 26 comment The integral $\int f \mu(dt)$ versus $\int f \mu(t) dt$ @Did: ah, I see. So I suppose that if you can solve $\int \alpha e^{-\alpha t} \mu(t) dt = 1$ and such an $\alpha$ exists, then $\mu(t) \ll e^{\alpha t}$ must hold. gotcha. Feb 26 comment The integral $\int f \mu(dt)$ versus $\int f \mu(t) dt$ @Did: after checking the details again, does this technically require us to assume that $\mu(t) < \infty$? not unreasonable I suppose. Feb 26 comment The integral $\int f \mu(dt)$ versus $\int f \mu(t) dt$ @Did: wow. that probably seemed completely obvious to you, but I never would've seen it this way. much appreciated. Feb 26 comment The integral $\int f \mu(dt)$ versus $\int f \mu(t) dt$ @echzhen yes. but my actual question goes a little beyond that. sorry, I've edited to make this clearer. Feb 26 revised The integral $\int f \mu(dt)$ versus $\int f \mu(t) dt$ changed the question to make it more pointed Feb 26 revised The integral $\int f \mu(dt)$ versus $\int f \mu(t) dt$ added 5 characters in body Feb 26 revised The integral $\int f \mu(dt)$ versus $\int f \mu(t) dt$ added 55 characters in body Feb 26 asked The integral $\int f \mu(dt)$ versus $\int f \mu(t) dt$ Feb 21 revised Intuition behind the renewal equation updated my understanding of the renewal measure... Feb 21 revised Upcrossings of the forward recurrence time deleted 44 characters in body