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Apr
8
revised What is the difference between ring homomorphism and module homomorphism?
added 25 characters in body
Apr
8
answered What is the difference between ring homomorphism and module homomorphism?
Apr
8
revised English for “prolongement” oder “Fortsetzung”?
edited tags
Apr
8
comment English for “prolongement” oder “Fortsetzung”?
+1 : I was just a little slow :)
Apr
8
answered English for “prolongement” oder “Fortsetzung”?
Apr
8
comment bibliography reference to clifford algebras
A straightforward Internet search, or at least a glance at English Wikipedia, turns up dozens of references. It does not sound like you looked.
Apr
8
comment Showing that a divisor of zero in a commutative ring with unity can have no multiplicative inverse"
Dear @nancy : I spotted the duplicate question in the related questions, indicating that it probably appeared in the list that appeared as you typed your question. Please try to do a search before you post a new question.
Apr
8
comment Must PID contain 1?
@user136266 I didn't claim that phrase appeared. I said that the description of the sum of two ideals presumes an identity. As I mentioned already, without identity you cannot say that (x)=xD. So (x)+(y) can't be described as xD + yD.
Apr
8
answered Regard naturally as modules.
Apr
8
comment Must PID contain 1?
@user136266 The very first line uses the "with identity" description of the sum of two ideals, so of course it does not literally work without identity.
Apr
8
comment Must PID contain 1?
"Proof by definition" does not really acknowledge the OP's question here... I suppose in certain cases it is the right answer...
Apr
8
comment Must PID contain 1?
@user136266 if you are taking a class, then yes, I'd say it's highly likely that assuming identity was intended. Do you have any reason to believe this might not be the case?
Apr
8
revised Must PID contain 1?
added 195 characters in body
Apr
8
answered Must PID contain 1?
Apr
8
comment Complex euclidean tensor products
You are asking three very broad questions in a single question, and so you are likely to get little attention and probably only partial responses. You ought to focus on your main question and try to build the others as follow-ups.
Apr
7
reviewed No Action Needed Using telescoping property to prove difference of powers
Apr
7
reviewed Leave Closed Has lack of mathematical rigour killed anybody before?
Apr
7
comment Is Spec R compact?
Dear @Mike : The question I duped this against was in the Related Questions to the right, which means it probably showed up as you were typing the question statement. Please use the search features before posting a question. Regards
Apr
7
revised Show that $R[x]/\langle x \rangle \cong R$ in a ring with 1
edited tags
Apr
7
comment Show that $R[x]/\langle x \rangle \cong R$ in a ring with 1
@sara It the simplest homomorphism that would first come to mind. You would like 1 in the polynomial ring to map to 1 in R, right? This hints at a more general homomorphism...