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2h
comment Riemann-Roch Theorem and Ideals of a Ring
If you are going to ask about a specific comment, perhaps you should give the exact comment you are talking about, rather than a vague half description of it.
10h
comment Simultaneously vanishing quadratic forms?
Conceptually you're just checking the intersection of the radicals of the forms... but I guess that isn't concrete enough?
12h
awarded  Enlightened
12h
awarded  Nice Answer
14h
comment Lattices and Hasse diagrams
@JavierArias It can be problematic to do a Hasse diagram for infinite sets. You can see that here for example. You can generate a Hasse diagram for any finite poset.
14h
revised Lattices and Hasse diagrams
added 54 characters in body
14h
comment Lattices and Hasse diagrams
@GitGud Good comparison :)
14h
answered Lattices and Hasse diagrams
15h
revised Is ideal an “anti-field”?
added 189 characters in body
16h
comment Is ideal an “anti-field”?
@A.Magnus added one more paragraph about the noncommutative ring situation.
16h
revised Is ideal an “anti-field”?
added 328 characters in body
17h
comment Ideals of non semi-simple group rings.
It's not semisimple, but it is still quasi-Frobenius. Since I'm not super comfortable with semidirect products, my intuition about the structure breaks down a bit. You might be able to compute directly what its central idempotents are, and therefore come to the conclusion that it splits as Derek described. I'd hope that'd give some members of your chain, and maybe by then you'd see some dimensionality fact that would help you sort out if your chain is maximal or not.
17h
comment Ideals of non semi-simple group rings.
Dear Derek : That's really cool! It's a great tragedy in my life that I've never had the time to pick up Magma. Might you be willing to share the code you used somehow? Perhaps as a gist? Regards
17h
revised Is ideal an “anti-field”?
added 19 characters in body
17h
answered Is ideal an “anti-field”?
17h
comment Some doubts about right ideals of a ring
A fortiori, the axioms of ring multiplication allow you to conclude $R$ is a right $R$ module with the ring multiplication as the action. That right ideals are the same thing as right submodules follows directly from the definitions. And finally yes, the quotient being a ring necessitates $T$ being a two-sided ideal. Is there any question left?
1d
revised Difference between torsion and zero divisor
added 88 characters in body
1d
comment Difference between torsion and zero divisor
I get the feeling you didn't read the definitions very carefully: how could they be considered the same? They're of a similar flavor, of course... but the definitions aren't identical...
1d
answered Difference between torsion and zero divisor
1d
comment Proof about the difference between right and left ideals in a ring
@JavierArias I think someone has already pointed out to you in your proof that if the $R$ in the proof is commutative, it will be proving a commutative ring has a left ideal that isn't a right ideal, which is absurd. The strategy of beginning with "Let $M$ be a module over a ring $R$..." and then proving not all left ideals are right ideals is doomed to failure for that reason.