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seen Jan 28 '13 at 2:52

I am currently working on completing a Calculus course through distance learning, and find it both interesting and challenging.


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comment Finding second derivative
I like this method of finding the solution. Can you elaborate on how you did this, if possible. I don't quite see the connection between the original statement and the application of trig principles.
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comment Finding second derivative
This looks like an interesting way to solve this question. However, I do not understand the connections you are making.
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accepted Finding second derivative
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asked Finding second derivative
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accepted General relationships of variables in expression
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comment General relationships of variables in expression
Thanks, I have edited the post.
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revised General relationships of variables in expression
added 169 characters in body
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asked General relationships of variables in expression
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comment Orthogonal Trajectories
Thank you, this is a great solution. The algebra at the end is very helpful. I see that two functions are orthogonal when, at a given point, their slopes are negative reciprocals of each other.