313 reputation
211
bio website
location
age
visits member for 2 years, 3 months
seen Jan 28 '13 at 2:52

I am currently working on completing a Calculus course through distance learning, and find it both interesting and challenging.


Jul
2
awarded  Curious
Feb
24
awarded  Popular Question
Feb
18
awarded  Notable Question
Sep
20
awarded  Popular Question
Sep
15
awarded  Popular Question
Sep
13
awarded  Popular Question
Apr
17
awarded  Yearling
Jul
22
comment Finding second derivative
I like this method of finding the solution. Can you elaborate on how you did this, if possible. I don't quite see the connection between the original statement and the application of trig principles.
Jul
22
comment Finding second derivative
This looks like an interesting way to solve this question. However, I do not understand the connections you are making.
Jul
22
accepted Finding second derivative
Jul
22
asked Finding second derivative
Jul
18
accepted General relationships of variables in expression
Jul
18
comment General relationships of variables in expression
Thanks, I have edited the post.
Jul
18
revised General relationships of variables in expression
added 169 characters in body
Jul
18
asked General relationships of variables in expression
Jul
10
comment Orthogonal Trajectories
Thank you, this is a great solution. The algebra at the end is very helpful. I see that two functions are orthogonal when, at a given point, their slopes are negative reciprocals of each other.
Jul
9
accepted Orthogonal Trajectories
Jul
9
asked Orthogonal Trajectories
Jul
6
comment Implicit differentiation question
My confusion is over the concept of y being treated as y(x), implicitly. Clearly, I don't see why y is treated this way. If I was to differentiate the same expression for x, then I would assume that x would be treated as x(y). That being said, I think that what was missing initially is that the relation between the two variables implies that one is a function of the other, depending on which one you are differentiating for. Additionally, my approach attempted to solve the rational side of the expression with out using the quotient rule. Thanks for your solution, it has cleared up my thinking
Jul
6
comment Implicit differentiation question
I meant to express that y is a function of x. My aim was to differentiate the top of bottom of the rational expression. Since the expression is a relation versus a function, I thought I had to differentiate y using the chain rule.