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Ascetic devoted to mathematics

MathJax basic tutorial and quick reference


Nov
5
comment An integral domain with the factorization property and gcd for every two elements is a UFD
Your answer is great. It was just me who was confused of something not related to your answer. Thank you :)
Oct
10
awarded  Nice Answer
Sep
30
awarded  Explainer
Sep
24
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Sep
20
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Sep
14
awarded  Nice Answer
Sep
10
accepted Is the function $f(n)=\begin{cases} 0,& \text{If $CH$} \\ 1,& \text{If $\lnot CH$} \end{cases}$ $\mu$-recursive?
Sep
10
comment Is the function $f(n)=\begin{cases} 0,& \text{If $CH$} \\ 1,& \text{If $\lnot CH$} \end{cases}$ $\mu$-recursive?
opps! ok, thank you
Sep
10
reviewed Approve Is the function $f(n)=\begin{cases} 0,& \text{If $CH$} \\ 1,& \text{If $\lnot CH$} \end{cases}$ $\mu$-recursive?
Sep
10
asked Is the function $f(n)=\begin{cases} 0,& \text{If $CH$} \\ 1,& \text{If $\lnot CH$} \end{cases}$ $\mu$-recursive?
Aug
23
accepted If $f\tau$ is continuous for every path $\tau$ in $X$, is $f:X\rightarrow Y$ continuous?
Aug
22
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Aug
11
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Jul
18
accepted Solutions to the PDE :$2V\frac{\partial I}{\partial V}+2W\frac{\partial I}{\partial W}=I$
Jul
17
awarded  Nice Question
Jul
17
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Jul
16
accepted An integral domain with the factorization property and gcd for every two elements is a UFD
Jul
16
comment An integral domain with the factorization property and gcd for every two elements is a UFD
OH I was a little confused. Thans for your answer.
Jul
16
comment An integral domain with the factorization property and gcd for every two elements is a UFD
Hi. Why is $(ab,pb)=(a,p)b$ ?
Jul
16
comment An integral domain with the factorization property and gcd for every two elements is a UFD
@Mathmo123 I also don't see while 3) implies 2)