| bio | website | |
|---|---|---|
| location | Singapore | |
| age | 25 | |
| visits | member for | 1 year, 1 month |
| seen | Apr 30 '12 at 16:33 | |
| stats | profile views | 4 |
|
Apr 15 |
comment |
Two stage cyclic queue is it that if i can actually draw out the state transition diagram it will be proved that it can be modeled as a BD process? |
|
Apr 15 |
comment |
Two stage cyclic queue ermm. there wont be cases in which N =0 or $N=n because if N=0 the next state may be N-1 which is 0-1 which is wrong, since this is wrong the other state cannot be n as well? the transition rate is actually the service rate of the two servers? |
|
Apr 15 |
comment |
Two stage cyclic queue oh so server B could end serving one of its customers first, in which case (N,n-N) is replaced by (N+1,n-N-1)? Am i correct? What do you mean when N = ___ or ___? the rate is dependent on the service rate of b for the second question? |
|
Apr 15 |
revised |
Two stage cyclic queue edited tags |
|
Apr 15 |
comment |
Two stage cyclic queue hmm i dont really understand. if its a closed system, there will be N customers at server A and n-N at server B, so after that server A will be processing the N+1 customer and n-N+1 customer at server B. is this what you are referring to? |
|
Apr 15 |
comment |
Two stage cyclic queue events that can happen next will be that the arrival rate of server B will be service rate of server A and arrival rate of server A will be service rate of server B? So the time taken will be dependent on the arrival rate? State after tt time will be (n-N, N)? Still a bit confused by what it is asking for though. |
|
Apr 15 |
asked | Two stage cyclic queue |