1,961 reputation
919
bio website
location Trondheim, Norway
age 26
visits member for 3 years, 9 months
seen 15 hours ago

I fancy topology.


Jul
2
awarded  Curious
May
19
comment What is the implication of seeing a power law in real data?
en.wikipedia.org/wiki/Scale-free_network
May
8
comment Constant Function over Connected, Compact Space
From compactness you can choose a finite subcover and by connectedness you find your desired result. It is OK.
May
8
comment aRb if and only if a=b or a-b=2^n for a natural number, n
@sally... Look at the very definition of your eq. rel.
May
8
comment aRb if and only if a=b or a-b=2^n for a natural number, n
but a=a (.....)
May
6
comment Construct an equilateral triangle given a line segment
Solve the equations involving the circles algebraically..?
May
3
comment Gradient and Swiftest Ascent
Yes, sure. Then I guess you want this: math.stackexchange.com/questions/686538/…
May
3
comment Gradient and Swiftest Ascent
math.stackexchange.com/a/176782/2900
May
3
comment Can someone explain Method of Lagrangian multipliers
See e.g. math.stackexchange.com/questions/176705/…
May
3
comment Find the remainder when 15! is divided by 31
How does 30! relate to 15! mod 31?
Apr
30
comment Elementary topology problem
I also see that you have not accepted a single answer to your latest questions, making me reluctant to help you out.
Apr
30
comment Elementary topology problem
Can you do the first part? Try to find a open neighbourhood around each point.
Apr
29
comment Number of induced graphs
@rschwieb: sure. Added a little something.
Apr
29
answered Number of induced graphs
Apr
29
comment Abstract Algebra- Proving normality
No, you are taking the intersection of all such sets.
Apr
29
comment Abstract Algebra- Proving normality
Yes, now take the intersection of all such sets.
Apr
29
comment Green Identities via Differential Forms
Thank you for the diff form and electromagnetics paper.
Apr
28
comment Every simply connected, closed 3-manifold is homeomorphic to the 3-sphere.
It is, in fact, easier in dimensions $n\geq 5$ (Top manifolds).
Apr
28
comment prove that $s=\left \{ x:\left | x \right |\geqslant 1\left. \right \} \right.\subseteq \mathbb{R}$ not open
Sure, you could do that. Or you could look at its complement.
Apr
27
comment Number of induced graphs
yeah, correct...