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 Jul 18 comment How are codes assigned value in Shannon Fano Coding? So I, II, III, IV and V are groups? May 7 comment How does it evaluate A XOR B XOR C? Thanks. Thats quite helpful. Jun 19 comment Integration and Limits Thanks a lot. I had actually forgotten to multiply the 2 outside with the second term. Jun 19 comment Integration and Limits Oh, Thankyou. Yes, I was applying linearity on it but did a mistake. Thanks a lot. Jun 19 comment Integration and Limits Would not we be integrating x separately and 2 separately? Jun 19 comment Integration and Limits Would not we be integrating x separately and 2 separately? Jun 17 comment Probability question regarding range Thankyou for helping. Dec 19 comment Practical implementation of Mathematics @PatrickDaSilva: I simply cant apply it in practical even if it is from course. Nov 26 comment What is the logical operator for but? @Svish: Yes we follow British English in Pakistan : Nov 7 comment $2+4+6+\cdots+2n=n^2+n$ by mathematical induction @Gilles: Thanks for pointing it. Its a wrong proposition Nov 6 comment $2+4+6+\cdots+2n=n^2+n$ by mathematical induction No, its the 2nd one which I want... Nov 6 comment Help create this relation @ArturoMagidin: It is the modulo operator. Nov 5 comment Proving $n! > n$ for $n > 2$ using mathematical induction @KaratugOzanBircan: Thanks Nov 5 comment What does this quantifier evaluates to? @KaratugOzanBircan: Yes it does mean that but why should I take x=5? Nov 5 comment Help create this relation calculatorpro.com/modulo-calculator This link and your answered helped a lot. Thanks Nov 4 comment Is this a valid function? @ArturoMagidin: Yes it is. Nov 4 comment Help create this relation @Rankeya: Sorry, I fixed it. It was a typo error. Nov 4 comment How to determine transitivity and intransitivity of this relation? @HenningMakholm: I got the point that you made but there is no pair for $(1,2)$ Nov 4 comment How to determine transitivity and intransitivity of this relation? @HenningMakholm: So what to do with $(1,2)$? It does not satisfy the condition.. Nov 4 comment How to determine transitivity and intransitivity of this relation? $(1,2)$ is there but $(2,1)$ is not there, so its intransitive, right?