Kaz

2,171 reputation

214

bio	website	kylheku.com
	location	Vancouver, Canada
	age
visits	member for	1 year, 1 month
	seen	1 hour ago
stats	profile views	160

Check out the TXR language http://www.nongnu.org/txr

	2,171 reputation	bio	website	kylheku.com	visits	member for	1 year, 1 month
214 badges		location	Vancouver, Canada		seen	1 hour ago

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1h	answered	How do you respond to “I was always bad at math”?
7h	comment	Submit papers: arxiv or vixra? A scholarly paper in mathematics can be partially incorrect by the inclusion of some wrong statement which doesn't invalidate its main result.
1d	revised	explaining the derivative of $x^x$ added 587 characters in body
1d	revised	explaining the derivative of $x^x$ added 587 characters in body
1d	answered	explaining the derivative of $x^x$
1d	comment	Can we get just $3$ from $\pi$? Pi includes its own ceiling, and one that doesn't have a gaping hole in it, and has decent overhang.
1d	comment	Can we get just $3$ from $\pi$? Ah, a statistician!
1d	comment	Can we get just $3$ from $\pi$? Sure thing. let $\epsilon = \pi$. Then, $\pi - (\epsilon - 3)$. :)
1d	comment	Can we get just $3$ from $\pi$? Hi, i'm in Computer Science. So this means that pretty much the 333....333rd digit of pi is always 3, right?
May 19	comment	What is $-i$ exactly? Dimensionally, or perhaps geometrically, $i$ is in fact a unit vector in the complex plane. It is multiplied by -1 exactly how a vector would be.
May 18	awarded	Nice Answer
May 18	comment	Prove that $\log X < X$ for all $X > 0$ Your argument seems to be that if we just reverse the logarithm into exponentiation, the answer is then obvious. We take the proposition $\log x < x$ and turn it into $2^y > y$ and Q.E.D. Well then, why isn't it just obvious that $\log x < x$. Why don't we have to prove that $2^y > y$?
May 17	comment	Complete the square for $f(x) = 2x^2 + 4x - 6$ I'm sorry you feel you've been mislead; perhaps your employment benefits cover counseling for this sort of thing.
May 17	comment	Complete the square for $f(x) = 2x^2 + 4x - 6$ If you want to sit here reloading the page for updates to the answer, that's your choice. Finding the minimum of a quadratic has everything to do with root finding because the minimum is at that domain value which is midway between the roots (whether they be complex or real). The roots are $A\pm \sqrt B$. $A$ is where the minimum or maximum occurs, and $\sqrt B$ is the displacement from there to either root.
May 17	answered	Why is boundary information so significant? — Stokes's theorem
May 17	comment	Complete the square for $f(x) = 2x^2 + 4x - 6$ @ErickWong Where does the answer say that the question is purely concerned with solving for $f(x) = 0$? However, "completing the square" is a root finding technique taught to school children. As far as I know, it doesn't have any other use.
May 17	revised	Is a Quadratic equation a function? Spelling.
May 17	revised	Complete the square for $f(x) = 2x^2 + 4x - 6$ added 481 characters in body
May 17	answered	Complete the square for $f(x) = 2x^2 + 4x - 6$
May 17	comment	Prove that $\log X < X$ for all $X > 0$ If $\log x \geq x$ for some $x$, indeed that must mean that $2^y \leq y$. But if we can just jump to the conclusion that this is nonsense by definition, why don't we just do that for $\log x \geq x$?