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1d
comment Help to in finding the Eigenvectors for the following $2\times2$ Matrix
@SCK If $\vec{v}$ is an eigenvector, then so is $-\vec{v}$. Some authors don't like a bunch of negative signs. So, your answer is okay.
2d
revised prove by induction that $29^n - 21^n$ is always divisible by $8$
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2d
answered How to specify each digit of a real number in decimal representation in set theory?
Nov
23
revised Help to in finding the Eigenvectors for the following $2\times2$ Matrix
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Nov
23
revised Help to in finding the Eigenvectors for the following $2\times2$ Matrix
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Nov
23
answered Help to in finding the Eigenvectors for the following $2\times2$ Matrix
Nov
23
reviewed Approve suggested edit on Help to in finding the Eigenvectors for the following $2\times2$ Matrix
Nov
23
comment Find limit as x approaches infinity of exponential functions
You can divide top and bottom by $3^{2x}$. Just make sure to divide all of the terms.
Nov
23
revised Find limit as x approaches infinity of exponential functions
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Nov
22
awarded  Popular Question
Nov
21
comment Show that the given transformation is linear, by showing it is a matrix transformation.
@mookid I figured I could get him the matrix and he could do the rest by showing what $(x,y)$ maps to for arbitrary $x$ and $y$ and checking it with the matrix. It seemed like this was homework.
Nov
21
answered Show that the given transformation is linear, by showing it is a matrix transformation.
Nov
21
awarded  Nice Answer
Nov
21
comment Liftings of Nullhomotopic Maps
@studiosus Yes it is. All maps from a contractible space are null homotopic. I am not demanding the map fix the endpoints. There is nothing about that in the question.
Nov
20
answered Liftings of Nullhomotopic Maps
Nov
20
comment An odd function $f$ is differentiable at zero. Prove $f'(0)=0$?
Your title says $f$ is odd. In the post you say $f'$ of an even function. So, is the function odd or even?
Nov
19
reviewed Close Finding the limit of a series
Nov
19
reviewed Leave Open Scaling axis on Mathematica's plots
Nov
18
comment Is it true that eigen spaces corresponds to eigen value of $D_pf$ form a basis for $T_pM$?
It depends on what $D_pf$ is, which depends on what $f$ is.
Nov
18
revised Is it true that eigen spaces corresponds to eigen value of $D_pf$ form a basis for $T_pM$?
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