yoyostein
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 Nov 21 awarded Nice Question Nov 21 comment Open set U whose outer measure is less than A + epsilon Thanks this is very helpful Nov 21 accepted Open set U whose outer measure is less than A + epsilon Nov 21 asked Open set U whose outer measure is less than A + epsilon Nov 20 comment Show G has a normal subgroup of a given index Nice and succinct answer Nov 19 asked Delta-complex structure on S^2 Nov 19 revised Boundary Homomorphism Orientation (Very Basic Homology Question) edited title Nov 19 asked Boundary Homomorphism Orientation (Very Basic Homology Question) Nov 19 comment Homology of hexagon Oh yes.. I think I see what has gone wrong. Thanks Nov 18 comment Analytic vs algebraic proof Fundamental theorem of algebra has complex analysis proof (analytic) and Galois theory proof (algebraic). Nov 18 comment Show $x^n+ax+b=0$ has most two solutions Could $x$ be plus minus of the expression you found? Then there would be two stationary points. Nov 18 comment Homology of hexagon $\partial_1 d=\dots=\partial_1 i=w-v\neq 0$ so I thought that $d,\dots, i$ do not belong in $\ker \partial_1$. Since only $a,b,c$ belong to $\ker \partial_1$, I concluded that it has rank 3. Nov 18 comment Homology of hexagon Thanks! For part 2, I did try to use RREF to check whether the six vectors are linearly independent (they seem to be). Is there anything wrong with my delta complex? Nov 18 accepted Homology of hexagon Nov 17 comment Cauchy sequence in $L^p$, existence of a set with finite measure, and integral is less than epsilon over the complement I just re-read your proof, and it is really amazing. How did you intuitively arrive at your proof? I can understand your proof, but don't know the idea behind how to approach such questions myself.. Nov 17 accepted Cauchy sequence in $L^p$, existence of a set with finite measure, and integral is less than epsilon over the complement Nov 17 answered Equivalence of elements in a ring Nov 17 asked Homology of hexagon Nov 16 comment Free group with relations Thanks, is it still true if we omit the commutator part, I.e [a,b]=...=1 Nov 16 comment Free group with relations Thanks! Can you explain a bit on the collapsing part?