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seen Jul 24 at 4:12

Jul
17
comment Inequality: $2\sqrt{xz}+2\sqrt{yz}+2\sqrt{xy}\geq 3x+3y+3z-3$
thanks! I followed through your instructive steps and it worked perfectly.
Jul
17
accepted Inequality: $2\sqrt{xz}+2\sqrt{yz}+2\sqrt{xy}\geq 3x+3y+3z-3$
Jul
17
asked Inequality: $2\sqrt{xz}+2\sqrt{yz}+2\sqrt{xy}\geq 3x+3y+3z-3$
Jul
15
accepted Definable with parameters (Example)
Jul
4
awarded  Good Question
Jul
2
awarded  Notable Question
Jul
2
awarded  Curious
Jul
2
awarded  Inquisitive
Jul
1
accepted Ways to study mathematics while commuting
Jun
28
comment If $4k^3+6k^2+3k+l+1$ and $4l^3+6l^2+3l+k+1$ are powers of two, how to conclude $k=1, l=2$
Thanks for the help! I think $S$ should be $S=2(x+y+1)(2(x^2-xy+y^2)+x+y+1)$ (with minus sign)
Jun
28
accepted If $4k^3+6k^2+3k+l+1$ and $4l^3+6l^2+3l+k+1$ are powers of two, how to conclude $k=1, l=2$
Jun
28
awarded  Nice Question
Jun
27
awarded  Popular Question
Jun
27
answered What do I not understand about one-to-one functions?
Jun
27
asked Ways to study mathematics while commuting
Jun
26
revised If $4k^3+6k^2+3k+l+1$ and $4l^3+6l^2+3l+k+1$ are powers of two, how to conclude $k=1, l=2$
added 189 characters in body
Jun
25
revised If $4k^3+6k^2+3k+l+1$ and $4l^3+6l^2+3l+k+1$ are powers of two, how to conclude $k=1, l=2$
edited title
Jun
25
asked If $4k^3+6k^2+3k+l+1$ and $4l^3+6l^2+3l+k+1$ are powers of two, how to conclude $k=1, l=2$
Jun
23
awarded  Nice Question
Jun
23
comment When is $(a^2+b)(b^2+a)$ a power of $2$?
I thought of this question myself, just experimenting :)