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Apr
12
comment inserting absolute value in Hilbert transform and a discrete version of Hilbert transform
Ah okay, I just copied what I had cited in a paper, I forgot they didn't supply the proof. I don't have access to it at the moment, but do they cite a paper by Marsden and Moreka (I probably have spelled that wrong, and there should be a third author, either Richards or Riemenschneider)? The proof might be in there. If not I will look again on Monday, I know I have seen it before.
Apr
11
revised inserting absolute value in Hilbert transform and a discrete version of Hilbert transform
deleted 9 characters in body
Apr
10
comment inserting absolute value in Hilbert transform and a discrete version of Hilbert transform
I neglected to mention, if it is not clear, you can do a change of variables in the Hilbert transform to look at is as $p.v.\int\frac{f(y)}{x-y}dy$, and same for the discrete version.
Apr
10
revised inserting absolute value in Hilbert transform and a discrete version of Hilbert transform
added 87 characters in body
Apr
10
answered inserting absolute value in Hilbert transform and a discrete version of Hilbert transform
Mar
2
comment M bounded if and only if $\sup\{|\langle x,y \rangle|:y\in M \}<\infty$
Also I think the UBP is used to show one direction of your claim that a set is bounded iff it is weakly bounded.
Mar
2
comment M bounded if and only if $\sup\{|\langle x,y \rangle|:y\in M \}<\infty$
Do you mean for every $x\in M$, the supremum in your first line is finite?
Mar
2
comment How to prove inequality in positives?
What is the inequality here? I see an equality.
Feb
27
comment Big error in basis of tensor product space
I am not exactly sure what you are asking. But one thing you might make note of is that the tensor product of any ONBs is an ONB for the tensor product space.
Nov
17
comment Inverse of a particular operator
What space are you acting the operator on? It is also likely to be unbounded. If you are looking at $C^\infty$ functions on $[0,1]$ for example, the sequence of functions $\sin(nx)$ should give a sequence whose uniform norm is unbounded when applying the operator.
Nov
17
asked $p$-stable Random Variables for $p>2$?
Nov
17
awarded  Nice Question
Oct
16
comment Find a subset of the real numbers
Yes, I understand that they are not open, I was trying to give a hint rather than the solution. But the problem asks for an open and dense subset of $\mathbb{R}$. No subset of the rationals would be open in $\mathbb{R}$.
Oct
16
comment Find a subset of the real numbers
A good starting question for you: Are the rationals open in the real numbers? If not, then you cannot use a subset of them.
Oct
16
answered Decoding / reverse engineering math content
Jul
2
awarded  Curious
Apr
28
revised Proof of integral inequality
Poster did not know Latex.
Apr
28
suggested approved edit on Proof of integral inequality
Apr
21
comment Limit of a Cosine Sequence
I chose the other for being very elementary, but I like this argument, it is a nice one to have in the back of my mind.
Apr
21
accepted Limit of a Cosine Sequence