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 Sep 23 asked Sampling Theorem for Lattices Aug 28 accepted Limit Help: $\lim_{x\to\infty} xe^{-a\frac{x}{\ln x}}$ Aug 28 comment Limit Help: $\lim_{x\to\infty} xe^{-a\frac{x}{\ln x}}$ Yep, thanks. I knew I was just not thinking of something obvious. Aug 28 asked Limit Help: $\lim_{x\to\infty} xe^{-a\frac{x}{\ln x}}$ Aug 3 accepted $p$-stable Random Variables for $p>2$? Jun 26 awarded Yearling Jun 26 comment How to extended a unitary operator to a larger space? Incidentally, I think the thing that makes the tensor "solution" incorrect is the fact that you can write $V$ as the sum of $W$ and its orthogonal complement, but not the tensor product of those. The dimensions don't agree because $W\otimes H$ has dimension $dim(W)dim(H)$ not $dim(W)+dim(H)$. Jun 26 answered How to extended a unitary operator to a larger space? Apr 12 comment inserting absolute value in Hilbert transform and a discrete version of Hilbert transform Ah okay, I just copied what I had cited in a paper, I forgot they didn't supply the proof. I don't have access to it at the moment, but do they cite a paper by Marsden and Moreka (I probably have spelled that wrong, and there should be a third author, either Richards or Riemenschneider)? The proof might be in there. If not I will look again on Monday, I know I have seen it before. Apr 11 revised inserting absolute value in Hilbert transform and a discrete version of Hilbert transform deleted 9 characters in body Apr 10 comment inserting absolute value in Hilbert transform and a discrete version of Hilbert transform I neglected to mention, if it is not clear, you can do a change of variables in the Hilbert transform to look at is as $p.v.\int\frac{f(y)}{x-y}dy$, and same for the discrete version. Apr 10 revised inserting absolute value in Hilbert transform and a discrete version of Hilbert transform added 87 characters in body Apr 10 answered inserting absolute value in Hilbert transform and a discrete version of Hilbert transform Mar 2 comment M bounded if and only if $\sup\{|\langle x,y \rangle|:y\in M \}<\infty$ Also I think the UBP is used to show one direction of your claim that a set is bounded iff it is weakly bounded. Mar 2 comment M bounded if and only if $\sup\{|\langle x,y \rangle|:y\in M \}<\infty$ Do you mean for every $x\in M$, the supremum in your first line is finite? Mar 2 comment How to prove inequality in positives? What is the inequality here? I see an equality. Feb 27 comment Big error in basis of tensor product space I am not exactly sure what you are asking. But one thing you might make note of is that the tensor product of any ONBs is an ONB for the tensor product space. Nov 17 comment Inverse of a particular operator What space are you acting the operator on? It is also likely to be unbounded. If you are looking at $C^\infty$ functions on $[0,1]$ for example, the sequence of functions $\sin(nx)$ should give a sequence whose uniform norm is unbounded when applying the operator. Nov 17 asked $p$-stable Random Variables for $p>2$? Nov 17 awarded Nice Question