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visits member for 3 years, 10 months
seen Dec 4 '13 at 20:41

Just me!


Jul
2
awarded  Curious
Mar
21
awarded  Popular Question
Nov
19
awarded  Critic
Nov
19
accepted $U^*\otimes V$ versus $L(U,V)$ for infinite dimensional spaces
Nov
19
asked $U^*\otimes V$ versus $L(U,V)$ for infinite dimensional spaces
Nov
6
comment Book about Tensor Product of Vector Spaces
Well... I guess you did not understand my question or I was not clear enough. I am not saying that I do not know this stuff. I am just asking for a reference!
Nov
5
asked Book about Tensor Product of Vector Spaces
Oct
27
accepted Cardinality of a vector space versus the cardinality of its basis
Oct
27
comment Cardinality of a vector space versus the cardinality of its basis
I guess I got it, but to be sure that I correctly understood: what you mean by $(F\times B)^{<\omega}$?
Oct
27
asked Cardinality of a vector space versus the cardinality of its basis
Oct
27
asked Infinite cardinal comparation
Oct
4
awarded  Yearling
Jun
17
accepted What does boson-type realization mean?
Jun
16
asked What does boson-type realization mean?
Mar
24
accepted Tilting modules
Mar
22
comment Tilting modules
Let me try to clarify something: in the setting which I am talking about, a tilting module is a module with a filtration by standard and costandard modules. The category has the property that any tilting module is isomorphic to a direct sum of indecomposable tilting modules. I am not sure about this name "characteristic tilting module".
Mar
21
comment Tilting modules
@Mariano: Thanks for the answers! I tried to make the question 2) more clear. What textbook do you suggest me?
Mar
21
revised Tilting modules
the question 2) was unclear as mentioned by another user!
Mar
21
asked Tilting modules
Feb
15
comment Does the Implicit mapping theorem imply the inverse mapping theorem?
@copper.hat I know about the equivalence, but I realized that I dont know how to prove it. With your suggestion, I found an application $C^1$ such that $f(g(x))=x$ under some conditions. I dont see why $g$ is the inverse of $f$, i.e $g(f(x))=x$. How should we proceed with your suggestion?