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May
1
revised Are there an infinite number of prime numbers where removing any number of digits leaves a prime?
Changed title grammatically
Apr
25
awarded  Nice Question
Apr
10
comment Number of zeroes in the disk $D(0; \frac{1}{4})$ - $f(z)=z^4-5z+1$
@george Take a look at the paper I cited.
Apr
10
revised Number of zeroes in the disk $D(0; \frac{1}{4})$ - $f(z)=z^4-5z+1$
added 102 characters in body
Apr
10
answered limit of $6x\sin(\frac{4}{x})$ as x approaches infinty
Apr
10
revised Number of zeroes in the disk $D(0; \frac{1}{4})$ - $f(z)=z^4-5z+1$
edited body
Apr
10
answered Number of zeroes in the disk $D(0; \frac{1}{4})$ - $f(z)=z^4-5z+1$
Apr
4
comment Compute $\mathrm{Res}(\frac{1+2z+3z^2}{1+z+z^2-3z^3},1)$
@TajMohamedBandalandabad Here is an outline of the proof.
Apr
4
revised Compute $\mathrm{Res}(\frac{1+2z+3z^2}{1+z+z^2-3z^3},1)$
Added proof of the residue computation theorem.
Apr
4
comment Compute $\mathrm{Res}(\frac{1+2z+3z^2}{1+z+z^2-3z^3},1)$
@TajMohamedBandalandabad Thanks. The residue computation gives the same answer.
Apr
4
revised Compute $\mathrm{Res}(\frac{1+2z+3z^2}{1+z+z^2-3z^3},1)$
edited body
Apr
4
answered Why this book says that $ 2^{1/2} = ±\sqrt{2} $?
Apr
4
answered Compute $\mathrm{Res}(\frac{1+2z+3z^2}{1+z+z^2-3z^3},1)$
Mar
27
comment Complex conjugate of an integral
Is this what you are asking: math.stackexchange.com/q/197642/27624
Mar
26
awarded  Yearling
Mar
16
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Mar
13
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Mar
11
answered Is f(x)=0 considered continous?
Mar
2
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Feb
12
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