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I am teaching myself mathematics ... poorly.


Jul
16
comment How to differentiate $\lim\limits_{n\to\infty}\underbrace{x^{x^{x^{…}}}}_{n\text{ times}}$?
Possible duplicate: math.stackexchange.com/q/138498/27624
Jul
2
awarded  Curious
Jul
2
awarded  Inquisitive
Jun
17
awarded  Popular Question
Jun
7
accepted Sum with binomial coefficients and a square root
Jun
2
awarded  Nice Question
May
20
awarded  Necromancer
May
5
awarded  Popular Question
Apr
21
awarded  Necromancer
Apr
21
awarded  Self-Learner
Apr
7
awarded  Benefactor
Apr
7
accepted Proving $\left(\sum_{n=-\infty}^\infty q^{n^2} \right)^2 = \sum_{n=-\infty}^\infty \frac{1}{\cos(n \pi \tau)}$
Apr
5
awarded  Nice Question
Apr
3
awarded  Promoter
Apr
3
revised Proving $\left(\sum_{n=-\infty}^\infty q^{n^2} \right)^2 = \sum_{n=-\infty}^\infty \frac{1}{\cos(n \pi \tau)}$
added 81 characters in body
Apr
1
comment Proving $\left(\sum_{n=-\infty}^\infty q^{n^2} \right)^2 = \sum_{n=-\infty}^\infty \frac{1}{\cos(n \pi \tau)}$
@MPW By convention, $q = e^{\pi i \tau}$ in the study of elliptic functions.
Apr
1
asked Proving $\left(\sum_{n=-\infty}^\infty q^{n^2} \right)^2 = \sum_{n=-\infty}^\infty \frac{1}{\cos(n \pi \tau)}$
Mar
30
awarded  Popular Question
Mar
28
comment “Simple” beautiful math proof
@izœc That is what you get if you solve for $x$ and $y$ in the formula. Complex numbers simply make the process more elegant and intuitive.
Mar
27
awarded  Nice Answer