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 May 1 revised Are there an infinite number of prime numbers where removing any number of digits leaves a prime? Changed title grammatically Apr 25 awarded Nice Question Apr 10 comment Number of zeroes in the disk $D(0; \frac{1}{4})$ - $f(z)=z^4-5z+1$ @george Take a look at the paper I cited. Apr 10 revised Number of zeroes in the disk $D(0; \frac{1}{4})$ - $f(z)=z^4-5z+1$ added 102 characters in body Apr 10 answered limit of $6x\sin(\frac{4}{x})$ as x approaches infinty Apr 10 revised Number of zeroes in the disk $D(0; \frac{1}{4})$ - $f(z)=z^4-5z+1$ edited body Apr 10 answered Number of zeroes in the disk $D(0; \frac{1}{4})$ - $f(z)=z^4-5z+1$ Apr 4 comment Compute $\mathrm{Res}(\frac{1+2z+3z^2}{1+z+z^2-3z^3},1)$ @TajMohamedBandalandabad Here is an outline of the proof. Apr 4 revised Compute $\mathrm{Res}(\frac{1+2z+3z^2}{1+z+z^2-3z^3},1)$ Added proof of the residue computation theorem. Apr 4 comment Compute $\mathrm{Res}(\frac{1+2z+3z^2}{1+z+z^2-3z^3},1)$ @TajMohamedBandalandabad Thanks. The residue computation gives the same answer. Apr 4 revised Compute $\mathrm{Res}(\frac{1+2z+3z^2}{1+z+z^2-3z^3},1)$ edited body Apr 4 answered Why this book says that $2^{1/2} = ±\sqrt{2}$? Apr 4 answered Compute $\mathrm{Res}(\frac{1+2z+3z^2}{1+z+z^2-3z^3},1)$ Mar 27 comment Complex conjugate of an integral Is this what you are asking: math.stackexchange.com/q/197642/27624 Mar 26 awarded Yearling Mar 16 awarded Popular Question Mar 13 awarded Nice Question Mar 11 answered Is f(x)=0 considered continous? Mar 2 awarded Nice Answer Feb 12 awarded Popular Question