Reputation
3,412
Top tag
Next privilege 5,000 Rep.
Approve tag wiki edits
2 11 38
Impact
~111k people reached

 Feb15 comment Examples of apparent patterns that eventually fail Sorry for being three years late, but I don't see what the deal is with the $\sqrt{163}$ sum. I mean, it's pretty cool, but what does it have to do with the question? Feb13 comment How is SO(2) compact according to this definiton? MathWorld's definition doesn't make a lot of sense, because usually you can't cover the whole group (or manifold in general) with a single coordinate chart. Dec15 comment How to calculate$\int_0^{\infty} e^{-x^2} \sin x dx$ in the most simple way @Lucian: My comment is not as useful as I thought it would be. It would work if the limits were $\pm \infty$ (of course, the integral would be zero), but it doesn't work here because after completing the square, the limits of integration are not simple. It does let you get to the Dawson function quickly, but I thought you could get a closed form solution. Dec15 comment How to calculate$\int_0^{\infty} e^{-x^2} \sin x dx$ in the most simple way Use $\sin x = (e^{ix}-e^{-ix})/2$. Nov13 comment Does the matrix exponential take open sets into open sets? @m.g.: Well, that was simple. You should post that as an answer. Nov13 comment Does the matrix exponential take open sets into open sets? @Jack: what about $x^2$ on $(-1,1)$? Oct8 comment How do I take the limit of this function? You must be doing something wrong: when I put in $2.1$, $2.01$, $2.001$, I get $15$, $150$, $1500$, etc. Jun16 comment Using dimensional analysis to evaluate $\frac{d}{dx}x^n$ @tpb261: I feel like the issue here, this being a man site and all, is showing that you can't make a non-constant dimensionless function out of only $x$. For all we know, there might be a constant $a$ with dimensions of length such that $c =x/a$. Jun16 comment I can't quite figure out this “separable equation” Small correction: having $\ln x$ in the equation already tells us that $x \neq 0$. Instead, you should assume that $x \neq 1$ so $\ln x \neq 0$. Jun16 comment Using dimensional analysis to evaluate $\frac{d}{dx}x^n$ I'm wondering if this would be a better fit at Physics, or if they would tell you that it's obviously correct. Jun7 comment How to explain the perpendicularity of two lines to a High School student? The question is about how to explain the fact that the product of the slopes is $-1$. Jun7 comment How to explain the perpendicularity of two lines to a High School student? I think you should read the question a little more. A high school student doesn't need real life examples to understand what "perpendicular" is. Apr27 comment Have you encountered this integral? I think you mean $P$ is the transform of $f$. Apr23 comment Taylor expansion of a not easily differentiable function @Fred: Taylor series around where? The function doesn't work for $x\le 1$, that's the problem. Apr13 comment Difficult Improper Integral What's so terrible about $\frac{114}{19}$? Feb6 comment For which constants does the following converge to a delta function? Depending on your definition of a delta function this may not be possible, since the integral of your function over $\mathbb{R}^2$ doesn't converge for any $n$, no matter what $c_n$ is. As far as I know, the delta function must verify $\int_\mathbb{R} \delta(x)\ dx = 1$. Feb5 comment Evaluating $\int \frac{1}{\sqrt{x^2 + a^2}}\, dx$ without resorting to trigonometric $u$-substitution Would you accept hyperbolic functions? :) Jan1 comment Is this a solution to the indefinite integral of $e^{-x^2}$? This is a nice idea, but I'm sorry to tell you that there's proof that there is no elementary formula for the integral. If you're okay with a series, just expand $e^{-x^2}$ and integrate term by term. Dec13 comment Can integration get the real value of $\pi$? @user3015600: You could, in principle, get $\pi$ with infinite precision. If you want any digit of the decimal expansion of $\pi$, there's a zillion formulas that you can use to get it. The problem is that we can never know all of them, not because math doesn't work, but simply because there's infinitely many of them and we don't have infinite time. Dec10 comment Explain complex numbers Also, I think this is a duplicate: math.stackexchange.com/questions/251665/…