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 Sep18 revised Basic set questions Forgot to answer the last part Sep18 answered Basic set questions Sep8 answered Simplifying expression with absolute value and unknown Aug23 comment A question on Taylor Series and polynomial I think the OP means that the Taylor series is finite. Aug22 answered In eigenvector calculations, why does $A-\lambda I$ need to be singular? Aug21 comment Graph $f(x)=\ln x+2$ @AustinBroussard: Yes, that's right. Aug21 comment Graph $f(x)=\ln x+2$ @AustinBroussard: I don't understand what you said about a horizontal asymptote having to do with $y \to \pm \infty$. A function has a horizontal asymptote, more or less, if it has a limit (not infinity) when $x$ goes to $\pm \infty$, and the logarithm doesn't have one. It simply goes to infinity. Aug21 comment Graph $f(x)=\ln x+2$ @AustinBroussard: This is a minor terminology thing. Rather than undefined, I would say that there is no y-intercept. The functions $\ln x$ and $\ln x + 2$ are undefined at $x=0$, so there is no y-intercept. Aug21 answered Graph $f(x)=\ln x+2$ Aug21 comment Graph $f(x)=\ln x+2$ Don't you mean $\ln x + 2$, or maybe $\ln(2+x)$? Aug13 comment Why can't $\int_0^1\sin(x^2) dx$ be equal to $2$? Forgive me if I'm missing something, but why would it be 2? I mean, with so many numbers to choose from, why would you expect it to be 2? Aug10 accepted Basic group theory exercise Aug10 asked Basic group theory exercise Aug6 comment Projectile Motion @ladaghini: Nothing, my mistake. Aug6 revised Projectile Motion missed a delta x Aug6 answered Projectile Motion Aug6 comment Projectile Motion @GorillaOne: Yes, sorry, I messed that up. I'll write an answer if I figure it out. Aug6 comment Projectile Motion @GorillaOne: If you know those, you can find out the time from $x=x_0+v_x t$ Aug1 comment Derivative of $x^x$ at $x=1$ from first principles @user758556: I guess to use L'Hôpital's you would have to know $\frac{\mathrm{d}}{\mathrm{d}h} (x+h)^h$, which sorts of defeats the purpose of using the limit definition in the first place. Jul29 answered Finding $a$ from $\lim\limits_{x\rightarrow0}(1+a\sin x)^{\csc x} =4$