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location Buenos Aires, Argentina
age 21
visits member for 3 years, 9 months
seen 2 hours ago

(my about me is currently blank)


Sep
21
comment Question about solving 2nd order linear differential equations
@Korgan: If it turns out you were right, please tell us, because this is the method I've seen in every differential equations book there is. I'd be very surprised if it was wrong.
Sep
20
revised Showing vectors span a vector space by definition
Expanded answer
Sep
20
comment Showing vectors span a vector space by definition
This indeed uses only the defintion. I'll edit to make it more explicit.
Sep
20
answered Showing vectors span a vector space by definition
Sep
18
revised Basic set questions
Forgot to answer the last part
Sep
18
answered Basic set questions
Sep
8
answered Simplifying expression with absolute value and unknown
Aug
25
comment Why $\pi$ was defined as the ratio of the circumference to the diameter instead of the radius?
I think this is a duplicate, but I can't find the other question. Basically, the answer was that the diameter is easier to measure than the radius.
Aug
23
comment A question on Taylor Series and polynomial
I think the OP means that the Taylor series is finite.
Aug
22
answered In eigenvector calculations, why does $A-\lambda I$ need to be singular?
Aug
21
comment Graph $f(x)=\ln x+2$
@AustinBroussard: Yes, that's right.
Aug
21
comment Graph $f(x)=\ln x+2$
@AustinBroussard: I don't understand what you said about a horizontal asymptote having to do with $y \to \pm \infty$. A function has a horizontal asymptote, more or less, if it has a limit (not infinity) when $x$ goes to $\pm \infty$, and the logarithm doesn't have one. It simply goes to infinity.
Aug
21
comment Graph $f(x)=\ln x+2$
@AustinBroussard: This is a minor terminology thing. Rather than undefined, I would say that there is no y-intercept. The functions $\ln x$ and $\ln x + 2$ are undefined at $x=0$, so there is no y-intercept.
Aug
21
answered Graph $f(x)=\ln x+2$
Aug
21
comment Graph $f(x)=\ln x+2$
Don't you mean $\ln x + 2$, or maybe $\ln(2+x)$?
Aug
13
comment Why can't $\int_0^1\sin(x^2) dx$ be equal to $2$?
Forgive me if I'm missing something, but why would it be 2? I mean, with so many numbers to choose from, why would you expect it to be 2?
Aug
10
accepted Basic group theory exercise
Aug
10
asked Basic group theory exercise
Aug
6
comment Projectile Motion
@ladaghini: Nothing, my mistake.
Aug
6
revised Projectile Motion
missed a delta x