Reputation
3,412
Top tag
Next privilege 5,000 Rep.
Approve tag wiki edits
2 11 38
Impact
~112k people reached

# 691 Actions

 Sep24 awarded Autobiographer Aug24 accepted Where does the right hand rule appear in the “tensor” definition of the cross product? Aug24 asked Where does the right hand rule appear in the “tensor” definition of the cross product? Jul24 answered Confusion about Spherical Coordinates Transformation Jul15 reviewed Edit nth term derivative with f(0) plugged in Jul15 revised nth term derivative with f(0) plugged in Improved formatting Jul2 awarded Curious Jul2 awarded Inquisitive Jun16 comment Using dimensional analysis to evaluate $\frac{d}{dx}x^n$ @tpb261: I feel like the issue here, this being a man site and all, is showing that you can't make a non-constant dimensionless function out of only $x$. For all we know, there might be a constant $a$ with dimensions of length such that $c =x/a$. Jun16 comment I can't quite figure out this “separable equation” Small correction: having $\ln x$ in the equation already tells us that $x \neq 0$. Instead, you should assume that $x \neq 1$ so $\ln x \neq 0$. Jun16 comment Using dimensional analysis to evaluate $\frac{d}{dx}x^n$ I'm wondering if this would be a better fit at Physics, or if they would tell you that it's obviously correct. Jun13 reviewed Approve Multiplicative inverse of $0$ Jun7 comment How to explain the perpendicularity of two lines to a High School student? The question is about how to explain the fact that the product of the slopes is $-1$. Jun7 comment How to explain the perpendicularity of two lines to a High School student? I think you should read the question a little more. A high school student doesn't need real life examples to understand what "perpendicular" is. May10 answered ∇×F (Curl) of a function of 4 variables? Apr27 comment Have you encountered this integral? I think you mean $P$ is the transform of $f$. Apr25 reviewed Approve Determinant of a sum of matrices Apr24 accepted Taylor expansion of a not easily differentiable function Apr23 answered Let $\int_a^bf(x)sgn(f(x)) + 2f(x) \ dx = 0$. Show that $f$ has at least one root. Apr23 comment Taylor expansion of a not easily differentiable function @Fred: Taylor series around where? The function doesn't work for $x\le 1$, that's the problem.