3,235 reputation
2830
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location Buenos Aires, Argentina
age 21
visits member for 3 years, 10 months
seen yesterday

(my about me is currently blank)


Aug
24
accepted Where does the right hand rule appear in the “tensor” definition of the cross product?
Aug
24
asked Where does the right hand rule appear in the “tensor” definition of the cross product?
Jul
24
answered Confusion about Spherical Coordinates Transformation
Jul
15
reviewed Edit suggested edit on nth term derivative with f(0) plugged in
Jul
15
revised nth term derivative with f(0) plugged in
Improved formatting
Jul
2
awarded  Curious
Jul
2
awarded  Inquisitive
Jun
16
comment Using dimensional analysis to evaluate $\frac{d}{dx}x^n$
@tpb261: I feel like the issue here, this being a man site and all, is showing that you can't make a non-constant dimensionless function out of only $ x $. For all we know, there might be a constant $ a $ with dimensions of length such that $ c =x/a $.
Jun
16
comment I can't quite figure out this “separable equation”
Small correction: having $\ln x$ in the equation already tells us that $x \neq 0$. Instead, you should assume that $x \neq 1$ so $\ln x \neq 0$.
Jun
16
comment Using dimensional analysis to evaluate $\frac{d}{dx}x^n$
I'm wondering if this would be a better fit at Physics, or if they would tell you that it's obviously correct.
Jun
13
reviewed Approve suggested edit on Multiplicative inverse of $0$
Jun
7
comment How to explain the perpendicularity of two lines to a High School student?
The question is about how to explain the fact that the product of the slopes is $-1$.
Jun
7
comment How to explain the perpendicularity of two lines to a High School student?
I think you should read the question a little more. A high school student doesn't need real life examples to understand what "perpendicular" is.
May
10
answered ∇×F (Curl) of a function of 4 variables?
Apr
27
comment Have you encountered this integral?
I think you mean $P$ is the transform of $f$.
Apr
25
reviewed Approve suggested edit on Determinant of a sum of matrices
Apr
24
accepted Taylor expansion of a not easily differentiable function
Apr
23
answered Let $\int_a^bf(x)sgn(f(x)) + 2f(x) \ dx = 0$. Show that $f$ has at least one root.
Apr
23
comment Taylor expansion of a not easily differentiable function
@Fred: Taylor series around where? The function doesn't work for $ x\le 1$, that's the problem.
Apr
20
asked Taylor expansion of a not easily differentiable function