Reputation
9,688
Next privilege 10,000 Rep.
Access moderator tools
Badges
1 13 30
Newest
 Nice Answer
Impact
~43k people reached

6h
answered Convergence of Sequence
7h
reviewed Leave Closed Solve a system of three equations
7h
reviewed Reopen Proof that $\sqrt6 - \sqrt2 - \sqrt3$ is irrational.
7h
reviewed Leave Open Gender Birth problem - Conditional probability
7h
reviewed Close Undetermined vs. Undefined
7h
reviewed Leave Open Do Cubic Splines Minimize Error?
7h
answered Gender Birth problem - Conditional probability
Jul
30
comment Is proving $m(E) < \epsilon, \forall \epsilon > 0$ equivalent to prove $m(E) = 0$?
However, in this case the set $F$ depends on $\delta$, which is different than the argument you quoted. So for each $\delta$ you can find such an $F$; there is not necessarily a single $F$ that works for every $\delta$.
Jul
30
comment Algebra2 help?!?!…
What progress have you made? Can you write down an equation expressing volume in terms of the temperature and pressure?
Jul
29
answered Find the sum of all primes smaller than a big number
Jul
29
revised Finding all the divisors of $a$ by decomposing it into the product $p^{\alpha_1}_{1} \cdot p^{\alpha_2}_{2} \cdots p^{\alpha_r}_{r}$
added 509 characters in body
Jul
29
comment Why does $\sqrt{6} + \sqrt{10} + \sqrt{15}$ have four conjugates?
Can you write down some conjugates and put them in your question? As it is, we can't understand for example whether you think it has more or fewer than four.
Jul
29
answered Given 4 points with 2 on different radius. Obtain the center of the circle.
Jul
29
answered Finding all the divisors of $a$ by decomposing it into the product $p^{\alpha_1}_{1} \cdot p^{\alpha_2}_{2} \cdots p^{\alpha_r}_{r}$
Jul
29
answered General formula for a specific problem?
Jul
27
comment What are the theorems in mathematics which can be proved using completely different ideas?
You can also prove this using group actions: $S_n$ acts on the set $\{1, 2, \dotsc, n\}$, and the stabilizer of any $k$-set from that set is $S_k\times S_{n-k}$. So by the orbit-stabilizer theorem, the number of such $k$-sets is the number of orbits, which is $\frac{|S_n|}{|S_k||S_{n-k}|} = \frac{n!}{k!(n-k)!}$.
Jul
24
comment Mathematical Induction proof for a cubic equation.
Did you intend the first line to say "then $x^{3n} =$ ..." rather than $x_{3n} = $...? If not, what is $x_i$?
Jul
24
revised Mathematical Induction proof for a cubic equation.
deleted 4 characters in body
Jul
24
revised Mathematical Induction proof for a cubic equation.
deleted 4 characters in body
Jul
20
comment Numbers divisible by all of their digits: Why don't 4's show up in 6- or 7- digit numbers?
It's not true for 6 digits, is it? How about 123984? If I've interpreted your question correctly, there are 248 such six-digit numbers, all but 12 of which contain a 4.