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May
22
awarded  Popular Question
Dec
18
comment In any Pythagorean triplet at least one of them is divisible by $2$, $3$ and $5$.
any explanation or hyperlink for the facts there?
Dec
18
asked In any Pythagorean triplet at least one of them is divisible by $2$, $3$ and $5$.
Sep
3
awarded  Scholar
Sep
3
awarded  Supporter
Sep
3
accepted Problem with basic probability concepts.
Sep
3
awarded  Editor
Sep
3
revised Problem with basic probability concepts.
added more questions
Sep
2
comment Problem with basic probability concepts.
so "again" doesn't mean anything? I thought due to "again"; question implies that all heads case should be considered. The "next" heads probability is 1/2; what about second question?
Sep
2
asked Problem with basic probability concepts.
Mar
23
awarded  Citizen Patrol
Mar
23
awarded  Student
Mar
23
comment contradicting PI=4 fallacy.
@KannappanSampath Okay. But I still don't get it. Those answers are still in "Mathematics" and I have a young brat(12 year old) to satisfy who wouldn't take any more mathematical terms.
Mar
23
comment contradicting PI=4 fallacy.
yes. you want to down vote? @KannappanSampath
Mar
23
asked contradicting PI=4 fallacy.
Mar
23
awarded  Autobiographer