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 Yearling
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Mar
22
awarded  Yearling
Feb
24
comment a.e.-defined integrable functions on $X$.
I think the answer is the following: let us denote the domain of the function $f$ by $D(f)\subset X$. The expression "a.e.-defined integrable functions on $X$" means that $\mu\big(X-D(f)\big)=0$ and $f$ is integrable in $D(f)$
Feb
13
asked Landsberg angle
Jan
18
comment Bi-asymptotic geodesics in Visibility manifolds
Thanks again. Our conversations on the subject have opened my eyes for several points on this theory.
Jan
18
accepted Bi-asymptotic geodesics in Visibility manifolds
Jan
13
comment Bi-asymptotic geodesics in Visibility manifolds
I see. It doesn't help. I can consider just $\mathbb{H}^2\times\mathbb{R}$.
Jan
13
comment Bi-asymptotic geodesics in Visibility manifolds
I have in addition the abscense of conjugate points, if it helps...
Jan
13
revised Bi-asymptotic geodesics in Visibility manifolds
added 40 characters in body
Jan
13
comment Bi-asymptotic geodesics in Visibility manifolds
Yes, you are completely right. I have wrote (and after I deleted it) the non-compact condition, but I thought it was perhaps unnecessary to comment. I will put this there to make more sense to the question. Thanks again!
Jan
13
asked Bi-asymptotic geodesics in Visibility manifolds
Oct
8
awarded  Tumbleweed
Oct
1
revised Deck transformations and Gromov Hyperbolicity
added 103 characters in body
Oct
1
asked Deck transformations and Gromov Hyperbolicity
Aug
11
revised Gromov hyperbolic metric spaces are quasi-convex
deleted 76 characters in body
Aug
11
comment Gromov hyperbolic metric spaces are quasi-convex
Thanks again for helping. That is what was missing for me to change the statement of the question.
Aug
5
comment Gromov hyperbolic metric spaces are quasi-convex
Actually, I don't know about the lower bound. In fact, all I was concerned about was the upper bound (I have to prove some sort of continuity here using the upper bound). I just put the entire statement the way I've read in a lecture note I have here. Reading after, I realized I do not need the upper bound. Perhaps it is not precise. I didn't thik much about the lower bound yet. I will try to understand. Perhaps I should change the way the question was proposed, so the answer corresponds to the question. What do you think?
Aug
5
accepted Gromov hyperbolic metric spaces are quasi-convex
Aug
5
comment Gromov hyperbolic metric spaces are quasi-convex
Ok! Now I've figured out! Thank you again!
Aug
5
comment Gromov hyperbolic metric spaces are quasi-convex
Perhaps I'm not figuring out what you mean by "moving endpoints of geodesics one at a time". Could you, if it doesn't bother you, perhaps fill out a little bit more details? Thank you very much again.
Aug
2
asked Gromov hyperbolic metric spaces are quasi-convex