matgaio
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 Mar22 awarded Yearling Feb24 comment a.e.-defined integrable functions on $X$. I think the answer is the following: let us denote the domain of the function $f$ by $D(f)\subset X$. The expression "a.e.-defined integrable functions on $X$" means that $\mu\big(X-D(f)\big)=0$ and $f$ is integrable in $D(f)$ Feb13 asked Landsberg angle Jan18 comment Bi-asymptotic geodesics in Visibility manifolds Thanks again. Our conversations on the subject have opened my eyes for several points on this theory. Jan18 accepted Bi-asymptotic geodesics in Visibility manifolds Jan13 comment Bi-asymptotic geodesics in Visibility manifolds I see. It doesn't help. I can consider just $\mathbb{H}^2\times\mathbb{R}$. Jan13 comment Bi-asymptotic geodesics in Visibility manifolds I have in addition the abscense of conjugate points, if it helps... Jan13 revised Bi-asymptotic geodesics in Visibility manifolds added 40 characters in body Jan13 comment Bi-asymptotic geodesics in Visibility manifolds Yes, you are completely right. I have wrote (and after I deleted it) the non-compact condition, but I thought it was perhaps unnecessary to comment. I will put this there to make more sense to the question. Thanks again! Jan13 asked Bi-asymptotic geodesics in Visibility manifolds Oct8 awarded Tumbleweed Oct1 revised Deck transformations and Gromov Hyperbolicity added 103 characters in body Oct1 asked Deck transformations and Gromov Hyperbolicity Aug11 revised Gromov hyperbolic metric spaces are quasi-convex deleted 76 characters in body Aug11 comment Gromov hyperbolic metric spaces are quasi-convex Thanks again for helping. That is what was missing for me to change the statement of the question. Aug5 comment Gromov hyperbolic metric spaces are quasi-convex Actually, I don't know about the lower bound. In fact, all I was concerned about was the upper bound (I have to prove some sort of continuity here using the upper bound). I just put the entire statement the way I've read in a lecture note I have here. Reading after, I realized I do not need the upper bound. Perhaps it is not precise. I didn't thik much about the lower bound yet. I will try to understand. Perhaps I should change the way the question was proposed, so the answer corresponds to the question. What do you think? Aug5 accepted Gromov hyperbolic metric spaces are quasi-convex Aug5 comment Gromov hyperbolic metric spaces are quasi-convex Ok! Now I've figured out! Thank you again! Aug5 comment Gromov hyperbolic metric spaces are quasi-convex Perhaps I'm not figuring out what you mean by "moving endpoints of geodesics one at a time". Could you, if it doesn't bother you, perhaps fill out a little bit more details? Thank you very much again. Aug2 asked Gromov hyperbolic metric spaces are quasi-convex