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1d
comment Is this simple drawing a category?
Yes. ${}{}{}{}{}$
1d
comment Local ring and zero divisors
@NECing, in what possible way this does not answer the question?!
1d
comment Diagrams characterizing ring characteristic, and in particular field characteristic 1?
Moreover, the field with one element is not a field (and it may not be at all, for all we know...)
1d
comment Diagrams characterizing ring characteristic, and in particular field characteristic 1?
I don't understand what you want.
1d
answered Is there a classification for the generating sets of symmetric group?
1d
answered Is this ring a well known ring and if so how is it called?
Oct
21
comment Exterior derivative of local basis element $dx^k$ is zero
You should give us what definition you are using of $dx^k$ and of the exterior differential, as the details of the proof depend on them.
Oct
19
comment space of solutions of a PDE
On the other hand: the statement of the problem makes no implication that one can deduce that the set of solutions for a fixed K is a vector space from the fact that there is «a fixed amount of solutions». As I said, the two things are completely independent.
Oct
19
comment space of solutions of a PDE
The set of solutions of a linear homogeneous PDE is always a vector space: that is, in fact, almost what it means for the equation to be linear and homogeneous!
Oct
19
comment space of solutions of a PDE
The fact that the set of solutions of the equation (for a fixed K) is a vector space is just a fact of nature, a consequence of the equation being linear homogeneous).
Oct
19
comment space of solutions of a PDE
I don't understand what you don't understand: what is to «link the two solutions in to a the equation being a vector space»? I don't see what two things you are trying to connect.
Oct
19
comment space of solutions of a PDE
If they are not the same function then you have two solutions.
Oct
19
comment space of solutions of a PDE
Well, are $\sin\pi x\sin\pi 2y$ and $\sin2\pi x\sin\pi y$ the same function? In any case, by «number of solutions» they probably mean number of «linearly independent solutions».
Oct
16
comment Questions related to the concept of $k$-algebras
In fact, what you describe as a motivation for studying algebras is not a motivation at all.
Oct
16
answered Questions related to the concept of $k$-algebras
Oct
14
answered Analogue in algebra for characteristic classes?
Oct
13
comment An alternative proof for the units of $U_q(\mathfrak{sl}_2)$ using Ore extensions.
The quantum group has nothing to do with this: just consider an Ore extension of a domain (with an automorphism and a derivation) and find its units.
Oct
13
comment Third isomorphism Theorem and Free groups
Then some words explaining why your first isomorphism holds would probably be useful!
Oct
13
comment Equation of a line tangent to circumference
Please remove the answer from the question body, and the «SOLVED» from the title (we don't do this title thing, as you'll notice if you browse the last 10000 questions! :-) )
Oct
13
comment Third isomorphism Theorem and Free groups
Are all the $\langle\cdots\rangle$ thingies normal subgroup closures?