# Mussri

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MN

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 Aug2 awarded Teacher Aug2 answered How to write t so that it doesn't look like a plus? May18 comment Signs in binomial expansionsThank you; the gears clicked into place! Once the exams are over, I'll put on an answer that's -hopefully- as intuitive as I get it now. May18 awarded Supporter May12 comment Signs in binomial expansionsThat doesn't tell why it was decided (apparently, that's how I was given it) that such terms, at face value, need the expansion with opposite signs. I added an (*) in the \$\$ so see there for what I meant. May12 asked Signs in binomial expansions May12 comment Conditions on roots of a quadraticTomorrow's the exam. I'm keeping all this in mind and hoping for he best... May12 awarded Scholar May12 accepted Conditions on roots of a quadratic Apr15 comment Conditions on roots of a quadratic Apr15 comment Conditions on roots of a quadratic@KannappanS, Discriminant! I wrote it the other way as I remembered its pronunciation in class... So many faults in my educational system... Anyway, it's ($\Delta = b^2-4ac$). Apr15 comment Conditions on roots of a quadraticHe asked for my trial on the second one and so I did... I never intended it to be un-respectful and I knew it doesn't work in questions yet I only wanted it visible as the answer he requested. Apr15 awarded Commentator Apr15 comment Conditions on roots of a quadraticNow what? {Extra Characters} Apr15 revised Conditions on roots of a quadraticAnswer 1 Apr15 comment Conditions on roots of a quadraticI tried it with the second and can't get the $x$ and $n+3$ out... Where can I post a photo? Apr15 comment Conditions on roots of a quadraticCan't delete prev. comments. - @JohannesK, Isn't Vieta's formula where we use a discrement to extract the roots? I tried but that didn't work. Apr15 comment Conditions on roots of a quadratic@GerryM, I'd said it was weird from the get go... It did actually use different case letters! - It's from my curriculum book, 10th grade equiv., Egypt. Apr15 comment Conditions on roots of a quadraticBut that would make $9a^2c = 2b^2$ which isn't the answer provided. It does seem logical and correct in steps but here they look for how good you followed the book even if it's incorrect. So I just need a confirmation that there's no other way to re-produce the answer provided. - I'll follow your steps and post the second one. Apr15 asked Conditions on roots of a quadratic