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visits member for 3 years, 11 months
seen Sep 11 at 14:18

Sep
5
awarded  Notable Question
Sep
4
awarded  Popular Question
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2
awarded  Popular Question
Aug
20
awarded  Nice Question
Jul
15
accepted prove that $ A^k$ is diagonalizable
Jul
15
accepted How to show that $\gcd(a,b) = ax+by \implies \gcd(x,y)=1$?
Jul
15
accepted How to find $\gcd(f_{n+1}, f_{n+2})$ by using Euclidean algorithm for the Fibonacci numbers whenever $n>1$?
Jul
15
accepted Let a|c and b|c such that gcd(a,b)=1, Show that ab|c
Jul
15
accepted Show that every prime $p>3$ is either of the form $6n+1$ or of the form $6n+5$
Jul
15
accepted How to prove by induction that $a^{2^{k-2}} \equiv 1\pmod {2^k}$ for odd $a$?
Jul
15
accepted How to show that integers $x_0+\frac{m}{d}t$, $t = 0, 1,…, d-1$, are pairwise incongruent modulo m.(Hint! Antithesis.)?
Jul
15
accepted How do you get possible candidates for primitive roots of 12?
Jul
15
accepted How to solve $x^3=-1$?
Jul
15
accepted How to show that $f-g$ is imaginary constant in $\mathbb{D}$?
Jul
15
accepted How to show that if $f$ or $g$ is continuous, then the convolution $f \star g$ of those functions is continuous?
Jul
15
accepted How to show by example that existence of barrier function of any set $U\subset \mathbb{C}$ is dependent of its set?
Jul
14
accepted How you'd show that $f$ is not continuous?
Jul
2
awarded  Curious
Jul
2
awarded  Inquisitive
Jun
30
comment How to show that if möbius transformation has an inverse, then it is injective?
But if you have $f(x)=x^2$(counter example) then $-1=a\neq b=1$, but still although $f$ has an inverse $f^{-1}=\sqrt{x}$, still $f(-1)=f(1)$. Am I missing something, if you know what I mean?