in_wolframAlpha_we_trust

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Sep
5
awarded  Nice Answer
Aug
4
comment Why is $f(x)=\sin (2x-\pi)$ the same as $g(x)=-\sin(2x)$?
@user50224 Look at my comment on your original posting.
Aug
4
comment Why is $f(x)=\sin (2x-\pi)$ the same as $g(x)=-\sin(2x)$?
Step E: If you move $\sin(2x)$ by $\pi$ you get $\sin(2(x - \pi)) = \sin(2x - 2\pi) = \sin(2x)$. What you have actually done is moved it right by $\pi/2$ which is only half a period, hence the negative.
Jun
13
comment how do we interpret this integral from polar co-ordinates
@DavidH For what it's worth, I'm pretty sure he wants your interpretation of the integral.
Jun
13
comment how do we interpret this integral from polar co-ordinates
@DavidH Indeed. I did ask in the comments what he intended but he was adamant they were the same $r$.
Jun
13
answered how do we interpret this integral from polar co-ordinates
Jun
13
comment how do we interpret this integral from polar co-ordinates
Should this really be $dr$?(and not $ds$?)
May
12
comment Numerical one-step method: initial value and non consistent method
I think your explanation is good.
Apr
29
comment How can I show that ~ is an equivalence relation such that $x$~$y$ if there is a continuous path in $M$ from $x$ to $y$?
@1950RobertLewis I understand he's not a great guy, but he makes great tools. My username should really be "in_wolfram_alpha_we_trust"
Apr
29
comment How can I show that ~ is an equivalence relation such that $x$~$y$ if there is a continuous path in $M$ from $x$ to $y$?
@1950RobertLewis Who would you have me follow? :P
Apr
29
comment How can I show that ~ is an equivalence relation such that $x$~$y$ if there is a continuous path in $M$ from $x$ to $y$?
What is the definition of an equivalence relation? What properties should it satisfy? How can we show that this relation satisfies these properties?
Apr
25
revised Explanation and Proof of the fourth order Runge-Kutta method
Minor edits.
Apr
8
comment Second order Diff. Equation
Yeah, I filled in the details. It looks like that integral doesn't have a solution in terms of elementary functions. This is (I think) the best we can do.
Apr
8
revised Second order Diff. Equation
added 417 characters in body
Apr
7
answered Second order Diff. Equation
Apr
7
comment Second order Diff. Equation
Now integrate both sides of the equation.
Apr
3
awarded  Informed
Mar
16
awarded  Yearling
Jan
17
revised (Highschool Pre-calculus) Solving quadratic via completing the square
Missing term in intermediate calculation
Jan
17
suggested suggested edit on (Highschool Pre-calculus) Solving quadratic via completing the square