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| bio | website | |
|---|---|---|
| location | ||
| age | ||
| visits | member for | 1 year, 2 months |
| seen | 8 hours ago | |
| stats | profile views | 283 |
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9h |
answered | $f(x)=|\cos x|+|\sin(2-x)|$ at which of the following point $f$ is not differentiable? |
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9h |
comment |
indirectly convex And $g(x) = \max\{x_{1},x_{2}\}$ instead of $x_{i}$? |
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10h |
revised |
Proving an operator is self-adjoint Added $$ necessary for TeX. |
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10h |
suggested | suggested edit on Proving an operator is self-adjoint |
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May 19 |
awarded | Nice Answer |
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May 17 |
answered | Simple Math Equation find sum of 4 numbers and if greater then number X reduce all 4 numbers respectively |
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May 17 |
comment |
Minimum number of coconuts Add a demo from Wolfram: demonstrations.wolfram.com/CoconutsSailorsAndAMonkey |
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May 17 |
awarded | Organizer |
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May 17 |
comment |
Minimum number of coconuts Here are some related problems with solutions, perhaps they will point you in the right direction: orion.math.iastate.edu/burkardt/puzzles/coconut_puzzle.html |
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May 17 |
revised |
Minimum number of coconuts edited tags |
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May 16 |
comment |
Timestepping PDE with positive eigenvalues Out of interest, where/how did this PDE arise? |
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May 16 |
revised |
Timestepping PDE with positive eigenvalues Corrected PDE. |
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May 16 |
suggested | suggested edit on Timestepping PDE with positive eigenvalues |
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May 16 |
answered | upper bound for $\frac{ax}{x-2}$ |
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May 16 |
comment |
solving $1+\frac{1}{x} \gt 0$ Yes, but how do we know what $1/x$ looks like? We should really take is derivative, show that it's decreasing everywhere, evaluate the limit at infinities and zero, look for intercepts and all that. |
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May 16 |
comment |
solving $1+\frac{1}{x} \gt 0$ @joneshf It needs a little bit of work to show that this really is the right way to draw $1 + 1/x$, and that it doesn't dip under the axis again at a later stage. |
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May 15 |
comment |
solving $1+\frac{1}{x} \gt 0$ \begin{document} \begin{tikzpicture}[] \draw[blue, thick, domain=-5:-1, samples = 250] plot (\x,{1/\x + 1}); \draw[red, thick, domain=-1:-0.3, samples = 250] plot (\x,{1/\x + 1}); \draw[blue, thick, domain=0.3:5, samples = 250] plot (\x,{1/\x + 1}) node [right] {$f(x) = 1 + \frac{1}{x}$}; \draw[black, thick, ->] (-6,0) -- (6,0) node[right] {$x$}; \draw[black, thick, ->] (0,-3) -- (0,5) node[above] {$y$}; \draw[black, thick, dashed] (-1,-3) -- (-1,0) node [below=0.25cm, left] {$-1$} -- (-1,5); \end{tikzpicture} \end{document} |
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May 15 |
comment |
solving $1+\frac{1}{x} \gt 0$ Thanks! It really does just take time and practice and some help from tex.stackexchange. |
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May 15 |
answered | solving $1+\frac{1}{x} \gt 0$ |
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May 15 |
comment |
How should we study maths? Merely memorizing proofs is a terrible way to study maths. Strive to understand and memorization will become unnecessary. |
