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seen Apr 17 at 12:08

Apr
8
comment Second order Diff. Equation
Yeah, I filled in the details. It looks like that integral doesn't have a solution in terms of elementary functions. This is (I think) the best we can do.
Apr
8
revised Second order Diff. Equation
added 417 characters in body
Apr
7
answered Second order Diff. Equation
Apr
7
comment Second order Diff. Equation
Now integrate both sides of the equation.
Apr
3
awarded  Informed
Mar
16
awarded  Yearling
Jan
17
revised (Highschool Pre-calculus) Solving quadratic via completing the square
Missing term in intermediate calculation
Jan
17
suggested suggested edit on (Highschool Pre-calculus) Solving quadratic via completing the square
Jan
16
revised What is Answer Of This Aptitude Question?
This is not mathematical physics.
Jan
16
suggested suggested edit on What is Answer Of This Aptitude Question?
Jan
15
comment Splitting a sandwich and not feeling deceived
@Paul That procedure is not coalition-resistant. After the players have rolled, the cutter can make the following offer to the first chooser "I will make no cuts, then you can choose the entire cake, and we shall split it among ourselves." This leaves the other $n-2$ players empty handed.
Jan
15
answered What does $f:[0, 1] \rightarrow [0,1]\times[0, 1]$ mean?
Dec
12
revised What is the minimum number that must share the same birthday (month & day) each year, given that one such birthday is February 29?
Added pigeonhole-principle tag.
Dec
12
suggested suggested edit on What is the minimum number that must share the same birthday (month & day) each year, given that one such birthday is February 29?
Dec
12
comment What is the minimum number that must share the same birthday (month & day) each year, given that one such birthday is February 29?
Are you asking for the minimum of the maximum number of people sharing a birthday?
Dec
11
comment Intuition behind precision with quadratures
Pretty much. Just check the quadrature and exact integrals of $x^{k}$ for increasing $k$ until you find a disagreement.
Dec
10
comment System of Differential Equations for Particular Initial Conditions
You have solved the equation for $y(t)$, now substitute into the equation for $x(t)$, i.e. $x' = x + e^{t}$. This is a first-order linear equation. You can solve it using an integrating factor.
Dec
10
revised Solve simple equation for d
Corrected tags. This has nothing to do with DEs.
Dec
10
suggested suggested edit on Solve simple equation for d
Dec
10
answered How to use Fourier Transform to solve the Airy's equation?