# in_wolfram_we_trust

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 Apr8 comment Second order Diff. Equation Yeah, I filled in the details. It looks like that integral doesn't have a solution in terms of elementary functions. This is (I think) the best we can do. Apr8 revised Second order Diff. Equation added 417 characters in body Apr7 answered Second order Diff. Equation Apr7 comment Second order Diff. Equation Now integrate both sides of the equation. Apr3 awarded Informed Mar16 awarded Yearling Jan17 revised (Highschool Pre-calculus) Solving quadratic via completing the square Missing term in intermediate calculation Jan17 suggested suggested edit on (Highschool Pre-calculus) Solving quadratic via completing the square Jan16 revised What is Answer Of This Aptitude Question? This is not mathematical physics. Jan16 suggested suggested edit on What is Answer Of This Aptitude Question? Jan15 comment Splitting a sandwich and not feeling deceived @Paul That procedure is not coalition-resistant. After the players have rolled, the cutter can make the following offer to the first chooser "I will make no cuts, then you can choose the entire cake, and we shall split it among ourselves." This leaves the other $n-2$ players empty handed. Jan15 answered What does $f:[0, 1] \rightarrow [0,1]\times[0, 1]$ mean? Dec12 revised What is the minimum number that must share the same birthday (month & day) each year, given that one such birthday is February 29? Added pigeonhole-principle tag. Dec12 suggested suggested edit on What is the minimum number that must share the same birthday (month & day) each year, given that one such birthday is February 29? Dec12 comment What is the minimum number that must share the same birthday (month & day) each year, given that one such birthday is February 29? Are you asking for the minimum of the maximum number of people sharing a birthday? Dec11 comment Intuition behind precision with quadratures Pretty much. Just check the quadrature and exact integrals of $x^{k}$ for increasing $k$ until you find a disagreement. Dec10 comment System of Differential Equations for Particular Initial Conditions You have solved the equation for $y(t)$, now substitute into the equation for $x(t)$, i.e. $x' = x + e^{t}$. This is a first-order linear equation. You can solve it using an integrating factor. Dec10 revised Solve simple equation for d Corrected tags. This has nothing to do with DEs. Dec10 suggested suggested edit on Solve simple equation for d Dec10 answered How to use Fourier Transform to solve the Airy's equation?