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May
6
revised How to determine the coordinate of roller coaster's wheels?
added 366 characters in body
May
6
asked How to determine the coordinate of roller coaster's wheels?
Mar
26
answered $\cos(x)+\cos(3x)+…\cos(2n-1)x=\sin(2nx)/2\sin(x)$
Mar
26
asked Is there any other method to solve $\sin x -\sqrt 3 \cos x=1$?
Mar
15
revised Integral by parts of this function
added 41 characters in body
Mar
15
answered Integral by parts of this function
Mar
15
accepted How to find 3-order $f(x)$ if its remainders are $2x-1$ and $3x-3$ when $f(x)$ is divided by $x^2+x-2$ and $x^2+x-3$, respectively?
Mar
15
awarded  Yearling
Mar
15
asked How to find 3-order $f(x)$ if its remainders are $2x-1$ and $3x-3$ when $f(x)$ is divided by $x^2+x-2$ and $x^2+x-3$, respectively?
Mar
12
accepted What is the explicit formula for the sequence representing the number of any triangles in a triangular grid?
Mar
12
accepted What are the names in English for Alterando, Invertendo, Componendo and Dividendo?
Mar
12
accepted How to prove that we cannot see more than 3 faces of an opaque solid cube simultaneously?
Mar
11
accepted How to find the closed solution for the following recursive vector equations?
Mar
11
accepted How to prove the number of images of two mirrors inclined at $A$ is $360/A -1$
Mar
11
accepted How can we analytically know 34! equals to zero for the following C# code?
Mar
11
comment How to prove that we cannot see more than 3 faces of an opaque solid cube simultaneously?
+1. Makes sense!
Mar
11
comment How to prove that we cannot see more than 3 faces of an opaque solid cube simultaneously?
But you can see 3 faces by focusing on one corner.
Mar
11
asked How to prove that we cannot see more than 3 faces of an opaque solid cube simultaneously?
Mar
1
asked How can we analytically know 34! equals to zero for the following C# code?
Feb
10
comment How to prove the number of images of two mirrors inclined at $A$ is $360/A -1$
+1 Short respons: I ask myself to prove it analytically. :-) I will give other comments later as I am teaching right now. :-) thanks.