Justin D.
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 Apr 19 awarded Notable Question Sep 13 awarded Popular Question Dec 4 awarded Notable Question Dec 2 awarded Popular Question Nov 22 awarded Popular Question Sep 24 awarded Popular Question Jul 2 awarded Curious Apr 15 awarded Popular Question Jan 29 revised taylor series for cosx around 0 LAtex formatting Jan 29 suggested approved edit on taylor series for cosx around 0 Jan 28 comment Proof that $AI_n = A$ using $Ab_i$. Thanks for the clarification! I had a hard time visualizing the matrices but you made it very clear. Thanks again. Jan 28 accepted Proof that $AI_n = A$ using $Ab_i$. Jan 27 comment Proof that $AI_n = A$ using $Ab_i$. OK so if I understand well, $I_n = [b_1 b_2 b_3 \dots b_n]$ where each $b_i$ is a column vector. When you say $A(b_1\dots b_n)$, is $(b_1\dots b_n)$ a matrix or $b_1 \cdot b_2 \cdot \dots \cdot b_n$? Jan 27 comment Proof that $AI_n = A$ using $Ab_i$. @ChristopherErnst, how is $I_n = (b_1\dots b_n)$? Is the definition using matrix multiplication? Jan 27 asked Proof that $AI_n = A$ using $Ab_i$. Nov 19 accepted Monotonic uniformly continuous function - Unique $f(t) = t$ Nov 18 comment Monotonic uniformly continuous function - Unique $f(t) = t$ OK, I understand your hint now. (it seems I was not in the right track... thanks!) Nov 18 comment Monotonic uniformly continuous function - Unique $f(t) = t$ @BettyMock, I am actually using Bolzano's Intermediate Value Theorem which I think does not require the endpoints to be of different signs Nov 18 comment Monotonic uniformly continuous function - Unique $f(t) = t$ @StephenMontgomery-Smith, I don't understand your hint. You want me to feed them into $|f(x)-f(x')| < |x-x'|$? Is the goal to show monotonicity or $f(t)=t$? Nov 18 asked Monotonic uniformly continuous function - Unique $f(t) = t$