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 Nov3 asked Singularities in (Elementary) Real Algebraic Geometry Oct5 accepted Prove that $\frac{d}{dx}\int_0^xf(x,y)dy = f(x,x)+\int_0^x\frac{\partial}{\partial x}f(x,y)dy$ Oct5 comment Prove that $\frac{d}{dx}\int_0^xf(x,y)dy = f(x,x)+\int_0^x\frac{\partial}{\partial x}f(x,y)dy$ super slick! =o Oct5 revised Prove that $\frac{d}{dx}\int_0^xf(x,y)dy = f(x,x)+\int_0^x\frac{\partial}{\partial x}f(x,y)dy$ [Edit removed during grace period] Oct5 asked Prove that $\frac{d}{dx}\int_0^xf(x,y)dy = f(x,x)+\int_0^x\frac{\partial}{\partial x}f(x,y)dy$ Sep25 accepted Let $b_n$ decrease monotonically to zero, prove $\sum b_nz^n$ converges for $|z|\leq 1$ and $z\neq 1$ Sep25 comment Let $b_n$ decrease monotonically to zero, prove $\sum b_nz^n$ converges for $|z|\leq 1$ and $z\neq 1$ @njguliyev oh nice, that does it right there, thanks. Sep25 asked Let $b_n$ decrease monotonically to zero, prove $\sum b_nz^n$ converges for $|z|\leq 1$ and $z\neq 1$ Sep21 comment Prove that if the Hessian of $f$ is positive definite at $a$, then the function attains a minimum at $a$ oh shoot you're right, ok that makes sense. Sep21 comment Prove that if the Hessian of $f$ is positive definite at $a$, then the function attains a minimum at $a$ not off the top of my head no, we've just been using this condition without explanation in a numerical optimization class. Sep21 comment Prove that if the Hessian of $f$ is positive definite at $a$, then the function attains a minimum at $a$ Are you sure? The wikipedia article doesn't mention it. Sep21 revised Prove that if the Hessian of $f$ is positive definite at $a$, then the function attains a minimum at $a$ added 27 characters in body Sep21 comment Prove that if the Hessian of $f$ is positive definite at $a$, then the function attains a minimum at $a$ I don't know about other conditions, I'm basing this off of en.wikipedia.org/wiki/… I guess it says the Hessian must be invertible as well. Sep21 comment Prove that if the Hessian of $f$ is positive definite at $a$, then the function attains a minimum at $a$ @JonathanY. I'm having trouble seeing how this shows positive curvature in all directions. Sep21 comment Prove that if the Hessian of $f$ is positive definite at $a$, then the function attains a minimum at $a$ You're right, I guess I should have specified for $n\geq 2$. Sep21 revised Prove that if the Hessian of $f$ is positive definite at $a$, then the function attains a minimum at $a$ added 36 characters in body Sep21 asked Prove that if the Hessian of $f$ is positive definite at $a$, then the function attains a minimum at $a$ Aug18 accepted Question on sufficient statistics Aug18 accepted Show that $(x+1+O(x^{-1}))^x = ex^x + O(x^{x-1})$ for $x\rightarrow \infty$ Aug15 revised Question on sufficient statistics deleted 2 characters in body