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comment Uniformly distributed independent random Variables
make a double integral $\int\int f(x)g(y)dxdy$ what are the bounds? what is $f(x)$ and $g(y)$? I suppose you'll need to use the fact that $P(a|b) = P(a,b)/P(b)$ as well
Mar
31
comment What is the $x$-intercept for $\frac{2x^2}{x^2-1} = 0$
no, I'm referring to multiplying both sides by the denominator of the fraction $x^2 + 1$
Mar
31
comment What is the $x$-intercept for $\frac{2x^2}{x^2-1} = 0$
clearing denominators is a common theme in algebraic simplification
Mar
31
comment What is the $x$-intercept for $\frac{2x^2}{x^2-1} = 0$
because you can just multiply both sides by the denominator and it disappears.
Mar
31
comment What is the $x$-intercept for $\frac{2x^2}{x^2-1} = 0$
what you have in your title is the equation you need to solve to find the x-intercepts, so just solve that equation, and you'll have them.
Mar
14
awarded  Yearling
Feb
7
awarded  Popular Question
Jan
28
revised Show both relaxations of boolean LP give equal lower bounds
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Jan
28
accepted Show both relaxations of boolean LP give equal lower bounds
Jan
28
answered Show both relaxations of boolean LP give equal lower bounds
Jan
22
revised Show both relaxations of boolean LP give equal lower bounds
added 94 characters in body
Jan
21
revised Show both relaxations of boolean LP give equal lower bounds
deleted 37 characters in body
Jan
21
revised Show both relaxations of boolean LP give equal lower bounds
deleted 52 characters in body
Jan
21
awarded  Citizen Patrol
Jan
20
revised Show both relaxations of boolean LP give equal lower bounds
edited body
Jan
20
revised Show both relaxations of boolean LP give equal lower bounds
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Jan
20
asked Show both relaxations of boolean LP give equal lower bounds
Jan
3
comment Function on convex set is convex if all rays are convex
skeptical that it's true?
Jan
3
comment Function on convex set is convex if all rays are convex
I know you can't for a general domain $D$, but if we assume that $D$ is open and convex I was wondering if you could.
Jan
3
asked Function on convex set is convex if all rays are convex