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1d
comment Find a basis and the dimension of the eigenspaces of the matrix
This is a symmetric matrix, hence its eigenspace has dimension 3 and you can just choose the standard basis for $\mathbb{R}^3$, no need to find the eigenvectors.
Apr
25
awarded  Popular Question
Apr
22
comment Diagonal decomposition, square root and eigenvector / eigenvalue of a matrix
assuming this matrix is even diagonalizable, to get $V$ and $D$ you need to already know the eigenvalues and eigenvectors, or you could just find $V$ and $D$ using computational software, otherwise I would suggest doing $Det(\lambda I - A)$ and seeing if you can factor the cubic.
Apr
17
comment Uniformly distributed independent random Variables
make a double integral $\int\int f(x)g(y)dxdy$ what are the bounds? what is $f(x)$ and $g(y)$? I suppose you'll need to use the fact that $P(a|b) = P(a,b)/P(b)$ as well
Mar
31
comment What is the $x$-intercept for $\frac{2x^2}{x^2-1} = 0$
no, I'm referring to multiplying both sides by the denominator of the fraction $x^2 + 1$
Mar
31
comment What is the $x$-intercept for $\frac{2x^2}{x^2-1} = 0$
clearing denominators is a common theme in algebraic simplification
Mar
31
comment What is the $x$-intercept for $\frac{2x^2}{x^2-1} = 0$
because you can just multiply both sides by the denominator and it disappears.
Mar
31
comment What is the $x$-intercept for $\frac{2x^2}{x^2-1} = 0$
what you have in your title is the equation you need to solve to find the x-intercepts, so just solve that equation, and you'll have them.
Mar
14
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Feb
7
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Jan
28
revised Show both relaxations of boolean LP give equal lower bounds
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28
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28
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22
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21
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20
revised Show both relaxations of boolean LP give equal lower bounds
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20
asked Show both relaxations of boolean LP give equal lower bounds