# Ron Jeremy

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bio website reddit.com/r/… location meatspace age member for 2 years, 4 months seen yesterday profile views 1,071

when someone smiles at me, all I see is an ape bearing its teethe

# 592 Actions

 Jun21 comment Resources for learning mathematics for intelligent people? Seriously though what numbers mean, peano axioms, you're going in the wrong direction. Get her a book on elementary algebra/trig and tell her to do all the problems, intuition and context is built up from the inside out Jun16 asked Hedging a long position-one period Jun10 comment How did we know to invent homological algebra? I don't know any homological algebra so maybe this isn't what you're looking for. But I know looking at short exact sequences is sometimes a useful way to look at a normal subgroup of a group and the associated quotient group: $N\rightarrow G\rightarrow G/N$. Jun9 comment Factor Rings of Polynomial Rings. Could you explain how you know $\varphi$ is a homomorphism? Jun4 accepted Understanding Conditional Expectation Jun4 comment Understanding Conditional Expectation Ok cool yah you're right, although I think you mean $E[X_k]=\frac{1}{2}$, since the coin is biased. Jun4 asked Understanding Conditional Expectation Jun2 revised Manipulation of probability integrals added 13 characters in body Jun2 revised Manipulation of probability integrals added 203 characters in body Jun2 revised Manipulation of probability integrals added 203 characters in body Jun2 revised Manipulation of probability integrals added 61 characters in body Jun2 asked Manipulation of probability integrals May31 revised Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$ edited body May31 revised Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$ deleted 4 characters in body May31 answered Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$ May30 revised Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$ added 164 characters in body May30 comment Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$ @Shuhao Cao en.wikipedia.org/wiki/Absolute_continuity#Generalizations_2 also in Royden's Real Analysis May30 revised Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$ added 192 characters in body May30 revised Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$ added 4 characters in body May30 comment Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$ @srijan this is essentially what I concluded about the function in my post. But I still don't see how there can be a set of measure zero on which the integral of $f'$ is non-zero.