# heat death

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bio website reddit.com/r/… location meatspace age member for 2 years, 1 month seen 10 hours ago profile views 1,037

when someone smiles at me, all I see is an ape bearing its teethe

# 589 Actions

 Jun8 asked Find the distribution of the random variable $X+Y$ Jun4 accepted Understanding Conditional Expectation Jun4 comment Understanding Conditional Expectation Ok cool yah you're right, although I think you mean $E[X_k]=\frac{1}{2}$, since the coin is biased. Jun4 asked Understanding Conditional Expectation Jun2 revised Manipulation of probability integrals added 13 characters in body Jun2 revised Manipulation of probability integrals added 203 characters in body Jun2 revised Manipulation of probability integrals added 203 characters in body Jun2 revised Manipulation of probability integrals added 61 characters in body Jun2 asked Manipulation of probability integrals May31 revised Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$ edited body May31 revised Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$ deleted 4 characters in body May31 answered Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$ May30 revised Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$ added 164 characters in body May30 comment Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$ @Shuhao Cao en.wikipedia.org/wiki/Absolute_continuity#Generalizations_2 also in Royden's Real Analysis May30 revised Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$ added 192 characters in body May30 revised Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$ added 4 characters in body May30 comment Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$ @srijan this is essentially what I concluded about the function in my post. But I still don't see how there can be a set of measure zero on which the integral of $f'$ is non-zero. May30 comment Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$ @Shuhao I know it's not of bounded variation, but I can't see how the measure theoretic definition of not being absolutely continuous can possibly be satisfied. May30 revised Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$ deleted 9 characters in body May30 asked Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$