1,690 reputation
417
bio website reddit.com/r/…
location meatspace
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visits member for 2 years, 9 months
seen Dec 4 at 3:52

when someone smiles at me, all I see is an ape bearing its teethe


Jun
21
comment Resources for learning mathematics for intelligent people?
Seriously though what numbers mean, peano axioms, you're going in the wrong direction. Get her a book on elementary algebra/trig and tell her to do all the problems, intuition and context is built up from the inside out
Jun
16
asked Hedging a long position-one period
Jun
10
comment How did we know to invent homological algebra?
I don't know any homological algebra so maybe this isn't what you're looking for. But I know looking at short exact sequences is sometimes a useful way to look at a normal subgroup of a group and the associated quotient group: $N\rightarrow G\rightarrow G/N$.
Jun
9
comment Factor Rings of Polynomial Rings.
Could you explain how you know $\varphi$ is a homomorphism?
Jun
4
accepted Understanding Conditional Expectation
Jun
4
comment Understanding Conditional Expectation
Ok cool yah you're right, although I think you mean $E[X_k]=\frac{1}{2}$, since the coin is biased.
Jun
4
asked Understanding Conditional Expectation
Jun
2
revised Manipulation of probability integrals
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Jun
2
revised Manipulation of probability integrals
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Jun
2
revised Manipulation of probability integrals
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Jun
2
revised Manipulation of probability integrals
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Jun
2
asked Manipulation of probability integrals
May
31
revised Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$
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May
31
revised Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$
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May
31
answered Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$
May
30
revised Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$
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May
30
comment Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$
@Shuhao Cao en.wikipedia.org/wiki/Absolute_continuity#Generalizations_2 also in Royden's Real Analysis
May
30
revised Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$
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May
30
revised Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$
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May
30
comment Showing that $f(x)=x\sin (1/x)$ is not absolutely continuous on $[0,1]$
@srijan this is essentially what I concluded about the function in my post. But I still don't see how there can be a set of measure zero on which the integral of $f'$ is non-zero.