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 Mar25 accepted borel measurable functions and measurable functions Mar25 comment borel measurable functions and measurable functions Thanks! Very neat construction! Mar25 comment borel measurable functions and measurable functions @PhoemueX Thanks, that solves the problem! Mar25 asked borel measurable functions and measurable functions Mar13 awarded Yearling Feb7 accepted boundary of the support of a continuous function Feb7 comment boundary of the support of a continuous function Thanks. That's a nice example! Feb7 asked boundary of the support of a continuous function Nov7 comment minimize p norm of f+c Never mind. I've already found a counter example. $e^x$ in $L^4$ doesn't follow this rule. Nov7 asked minimize p norm of f+c Sep21 revised determinant in terms of quadratic form evaluated at a point deleted 605 characters in body; edited tags; edited title Sep21 awarded Citizen Patrol Sep21 comment determinant in terms of quadratic form evaluated at a point @copper.hat I sincerely apologize for that. I am deleting this post. Sep21 comment determinant in terms of quadratic form evaluated at a point @WillJagy I am not trying to offend any of you. Perhaps what I said is not so polite. I apologize for that. Also to copper.hat. I can't at two users in one comment. Sep21 comment determinant in terms of quadratic form evaluated at a point This is not what I asked anyway. Towards the end, if you note that $A^*=det(A)A^{-1}$ you just got what I said in my post "A simple calculation reveals" . Sep21 comment determinant in terms of quadratic form evaluated at a point @WillJagy $n=1$ doesn't yield anything interesting. By positive definite I meant symmetric positive definite. Personally, I don't believe there is a relationship. If one just take $b$ to be an eigenvector, then the quantity given above would just be the product of the $n-1$ remaining eigenvalues. Since determinant is the product of $n$ eigenvalues, there is no guarantee that one might be bigger than the other. It all depends on whether the last eigenvalue is bigger or smaller than 1. The person who told me this seemed very certain. So I decided to ask in case people here have seen this before. Sep21 comment determinant in terms of quadratic form evaluated at a point @WillJagy Do you know that such a formula exists or are you just making a general comment? Sep21 asked determinant in terms of quadratic form evaluated at a point Sep6 awarded Tumbleweed Aug30 asked Does symmetric decreasing rearrangement of a smooth function preserves smoothness?