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2d
comment A question on homeomorphism definition
WOuld you be able to elaborate more on that example? The inverse is $T^{-1} = (arccos, arcsin)$ Also, even though it maps points close together, it is not the same; so I don't see the problem.
2d
asked A question on homeomorphism definition
2d
comment What does this statement actually mean?
I want to ask a question relating to $(3)$ and $(1)$. Why is $B_\epsilon$ being closed an important result here then? Or is this really just a small lemma to help the bigger result, and nothing more?
2d
comment What does this statement actually mean?
I am actually asking what does the set $B$ even mean?
Apr
21
revised What does this statement actually mean?
added 18 characters in body
Apr
21
comment What does this statement actually mean?
Thank you for that, edited.
Apr
21
asked What does this statement actually mean?
Apr
21
reviewed Approve suggested edit on Determining the matching number of a graph given maximal matchings.
Apr
21
reviewed Approve suggested edit on Convergence test for this function?
Apr
21
comment Find Determinant of A
Use the zeros in the first column.
Apr
21
accepted Uniform Convergence; Continuity
Apr
21
asked Oscillation of $f$ equal to $0$ implies continuity
Apr
20
comment Boundary and closure of a measure zero set is not measure zero?
So I am right…? Why does the Lebsegue measure here proves that no other measures can yield measure zero?
Apr
20
comment Boundary and closure of a measure zero set is not measure zero?
@AndreasBlass, you mentioned that no other nonemepty open sets could have measure $0$ in $\mathbb{R}^n$. Is it because that if I take $S = \{ (a - \epsilon/2, b + \epsilon/2) \}$ as an cover for $(a,b)$, then we have $V(S) = b - a + \epsilon < \epsilon$? I used the Lesbegue measure here.
Apr
20
comment Boundary and closure of a measure zero set is not measure zero?
Okay, I completely misunderstood the problem then. So my idea about being closed sets answers another question then?
Apr
20
comment Boundary and closure of a measure zero set is not measure zero?
But how do you know $E$ is the rationals?
Apr
20
revised Boundary and closure of a measure zero set is not measure zero?
edited body
Apr
20
comment Boundary and closure of a measure zero set is not measure zero?
Why can we take $E = \mathbb{Q}$? What if $\mathbb{Q} \subset E$?
Apr
20
comment Boundary and closure of a measure zero set is not measure zero?
How do we know $E$ is finite?
Apr
20
comment Antiderivative of $e^{au}$
Reverse chain rule, one antiderivative is $e^{au}/a$ assuming you are integrating wrt $u$ of course.