Bojan Vasiljević
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 Apr20 comment Given the factors of $N$, is there a method for computing the factors of $N-1$ or $N+1$? Generally and "sadly" the same way as with Fermat factorization method. Although I have found some exceptions as it is with the main branch of odd Collatz. Maybe there are some more complicated patterns in other branches. Apr18 revised Given the factors of $N$, is there a method for computing the factors of $N-1$ or $N+1$? added 6 characters in body Apr18 revised Given the factors of $N$, is there a method for computing the factors of $N-1$ or $N+1$? added 24 characters in body Apr18 revised Given the factors of $N$, is there a method for computing the factors of $N-1$ or $N+1$? added 40 characters in body Apr18 revised Given the factors of $N$, is there a method for computing the factors of $N-1$ or $N+1$? deleted 27 characters in body Apr18 answered Given the factors of $N$, is there a method for computing the factors of $N-1$ or $N+1$? Nov22 awarded Informed Aug15 awarded Teacher Dec27 revised $5n+1$, $3n-1$ problem, smallest repeating cycle and Collatz conjecture added 5 characters in body Dec27 revised $5n+1$, $3n-1$ problem, smallest repeating cycle and Collatz conjecture added 365 characters in body Dec26 accepted $5n+1$, $3n-1$ problem, smallest repeating cycle and Collatz conjecture Dec26 revised $5n+1$, $3n-1$ problem, smallest repeating cycle and Collatz conjecture added 320 characters in body Dec26 revised $5n+1$, $3n-1$ problem, smallest repeating cycle and Collatz conjecture edited title Dec25 revised $5n+1$, $3n-1$ problem, smallest repeating cycle and Collatz conjecture added 80 characters in body Dec25 revised $5n+1$, $3n-1$ problem, smallest repeating cycle and Collatz conjecture edited body Dec25 asked $5n+1$, $3n-1$ problem, smallest repeating cycle and Collatz conjecture Dec24 accepted $N \equiv 3 (\textrm{mod } 4)$ and Collatz conjecture Dec23 revised $N \equiv 3 (\textrm{mod } 4)$ and Collatz conjecture edited body Dec23 awarded Custodian Dec23 reviewed Approve $N \equiv 3 (\textrm{mod } 4)$ and Collatz conjecture