524 reputation
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bio website robertfilter.net
location Jena, Germany
age 31
visits member for 3 years, 6 months
seen Jan 23 at 12:55

If you like electrodynamic problems with solutions and their connections to current research, please visit www.problemsinelectrodynamics.com


Jan
12
awarded  Commentator
Jan
12
comment What is the key to success for a mathematician?
True, especially the last paragraph.
Jan
11
asked Stochastic interpretation of Einstein Equations
Jan
11
comment Relation of Brownian Motion to Helmholtz Equation
Thank you very much for your thorough answer. By generalizing and giving further examples you even put the story in a very nice context. I don't know but the relationship between such PDE's and stochastical processes seems to me like a nice ansatz for a unification of general relativity with the standard model.
Jan
11
accepted Relation of Brownian Motion to Helmholtz Equation
Jan
10
awarded  Cleanup
Jan
10
revised Relation of Brownian Motion to Helmholtz Equation
rolled back to a previous revision
Jan
10
comment Relation of Brownian Motion to Helmholtz Equation
Thank you for your answer. Indeed, one can find almost everything on the net - if one knows the right question :)
Jan
10
comment Relation of Brownian Motion to Helmholtz Equation
@Raskolnikov: Thank you for the further inside. It looks like this might be exactly what one would need :)
Jan
10
comment Relation of Brownian Motion to Helmholtz Equation
Thank you for the note, @Raskolnikov. So, do you think that there is any chance one could relate the Brownian walker to a "heat-like" equation $\Delta\psi + k^2\psi = \alpha\partial_{t}\psi$? Greets
Jan
10
asked Relation of Brownian Motion to Helmholtz Equation
Jan
9
answered Got to learn matlab
Jan
8
accepted $2\cdot\int_0^\infty \frac{a-u^2}{\left( u^2+\frac{a^2}{b-a}\right) \left(u^2+\frac{b^2}{b-a} \right) \sqrt{\cdots } }\mathrm {d}u $
Jan
7
answered $2\cdot\int_0^\infty \frac{a-u^2}{\left( u^2+\frac{a^2}{b-a}\right) \left(u^2+\frac{b^2}{b-a} \right) \sqrt{\cdots } }\mathrm {d}u $
Jan
6
comment $2\cdot\int_0^\infty \frac{a-u^2}{\left( u^2+\frac{a^2}{b-a}\right) \left(u^2+\frac{b^2}{b-a} \right) \sqrt{\cdots } }\mathrm {d}u $
@Moron: Thank you for the push :) I hope it is much more convenient now. Greets
Jan
6
awarded  Editor
Jan
6
revised $2\cdot\int_0^\infty \frac{a-u^2}{\left( u^2+\frac{a^2}{b-a}\right) \left(u^2+\frac{b^2}{b-a} \right) \sqrt{\cdots } }\mathrm {d}u $
Clearified question
Jan
6
comment $2\cdot\int_0^\infty \frac{a-u^2}{\left( u^2+\frac{a^2}{b-a}\right) \left(u^2+\frac{b^2}{b-a} \right) \sqrt{\cdots } }\mathrm {d}u $
@Moron: Thank you to point out that my question is not really clear. I want to calculate the given integral with respect to the constant $a$ and $b$. Today, I tried to calculate the contribution at the pole via Cauchy principal value integration but my vanishing result seams erroneous. I think I am just missing some basic "singular" integral skills to calculate the integral efficiently and I thought this might be just the right place to ask :) PS.: I will update the question tomorrow due to my further calculations. Sincerely
Jan
6
asked $2\cdot\int_0^\infty \frac{a-u^2}{\left( u^2+\frac{a^2}{b-a}\right) \left(u^2+\frac{b^2}{b-a} \right) \sqrt{\cdots } }\mathrm {d}u $
Dec
22
answered How to check if transformation is affine?