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May
20
asked Analysis of Optimizatiointechniques: Regret Analysis vs. Direct convergence?
May
18
revised Smooth approximation of maximum using softmax?
edited body
May
17
revised Closed form for sequence: $\sum_{j=1}^k 2^j j^{1/2}$
added 4 characters in body
May
17
asked Closed form for sequence: $\sum_{j=1}^k 2^j j^{1/2}$
May
5
revised Finding $Q$ for any $A$ s.t. $QAQ^\top = I$
added 8 characters in body
May
5
comment Finding $Q$ for any $A$ s.t. $QAQ^\top = I$
@AlgebraicPavel I literally do whatever you just suggested. But is it the best way we can do this? I want to get rid of the inversion D^-0.5
May
5
comment Finding $Q$ for any $A$ s.t. $QAQ^\top = I$
@AlgebraicPavel Ah I had this. Mistakenly removed. Added PSD to the definition.
May
5
revised Finding $Q$ for any $A$ s.t. $QAQ^\top = I$
added 8 characters in body
May
5
comment Finding $Q$ for any $A$ s.t. $QAQ^\top = I$
Sorry for confusion. Suppose $A$ is invertible. I corrected the definition.
May
5
revised Finding $Q$ for any $A$ s.t. $QAQ^\top = I$
added 8 characters in body
May
5
asked Finding $Q$ for any $A$ s.t. $QAQ^\top = I$
May
4
accepted Approximation of combination $ {n \choose k} = \Theta \left( n^k \right) $?
May
3
revised Approximation of combination $ {n \choose k} = \Theta \left( n^k \right) $?
added 38 characters in body
May
3
comment Approximation of combination $ {n \choose k} = \Theta \left( n^k \right) $?
Thanks. Let's assume that it is fixed. I added to the question. Could you give hints on the proof?
May
3
asked Approximation of combination $ {n \choose k} = \Theta \left( n^k \right) $?
Apr
20
awarded  Popular Question
Apr
11
asked if $f$ is in Banach space, then $\nabla f $ is in the dual space?
Mar
30
revised Is $ \frac{ x^T A A x }{ 1+ x^TAx} $ is upperbounded by the biggest eigenvalue of $A$?
added 14 characters in body
Mar
30
comment Is $ \frac{ x^T A A x }{ 1+ x^TAx} $ is upperbounded by the biggest eigenvalue of $A$?
Sry I forgot to mention: $A$ is psd. updated.
Mar
30
comment Is $ \frac{ x^T A A x }{ 1+ x^TAx} $ is upperbounded by the biggest eigenvalue of $A$?
I attached the source of the claim.