# ca11111

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 1d comment What is exponentiation? isn't $a^{\pi} < max(a^3,a^4)$ enough to say it's convergent (since it's also increasing with your decomposition) Dec2 comment Calculate interests I'm currently googling to know which option is commonly used, thx Dec2 comment Calculate interests yes r: yearly interests of the loan and m: monthly payback, @AndréNicolas I have edited the question with what you suggested can you have a look? Dec2 comment Calculate interests I don't agree, at the end of first year, the loan is N less 12 paybacks, and you add the interests Dec2 comment Calculate interests ok else, to me, for the amount at beginning of years: $N_y = N_{y-1} - 12m + r(N_{y-1}-6m)$ no? (you have put $12m$ also multiplied by r) Dec2 comment Calculate interests seems x and y are mixed, it's V(x,b... ) above? Dec2 comment Calculate interests @AndréNicolas I thought when you do a loan, the interests were added at the end of the year only, but it's probably each months, it would increase slightly the result. yes r is the nominal interest rate (e.g. 2.5%), @ Limitless thx trying to understand it Jun29 comment combinatorics counting sets with a one element having values in another set yes i know, it's a data indexation problem, and the solution in the post scales better than putting all elts inline Jun27 comment combinatorics counting sets with a one element having values in another set and seems also it will better scale than putting all the k elts inline $2^{n-1+k}-1$ Jun27 comment combinatorics counting sets with a one element having values in another set ok and seems to work for the example, thx May31 comment how many different possible pairs are there in a n-tuple? @Shaktal $(n)_a$ is $\binom{n}{a} * a!$ like said in the ncmath's answer? May31 comment how many different possible pairs are there in a n-tuple? ah right (a,b) and (b,a) is the same unordered pair May30 comment Integer sequence comparison, binomials Vs power yes wrong calcul May30 comment Integer sequence comparison, binomials Vs power it's round(x)-1 May30 comment how many different possible pairs are there in a n-tuple? there should be more unordered than ordered? May30 comment how many different possible pairs are there in a n-tuple? what is equal your second result $(n)_2$, please May30 comment factorial Vs power sequence well I see your point n! is > a^n for n>a/2 right? May30 comment factorial Vs power sequence you could give a simple proof, something like n! > (n/4)^n for n>5 maybe May13 comment funny complex equality 1 = -1 well had to search far in the answers, gary's answer seems good, tx May12 comment funny complex equality 1 = -1 could you reopen the question, the said duplicates are not