| bio | website | combinatorialgames.wordpress.… |
|---|---|---|
| location | Somewhere | |
| age | 25 | |
| visits | member for | 1 year, 2 months |
| seen | yesterday | |
| stats | profile views | 61 |
I have years of experience helping people with math(s) on academic forums, over the internet, and in person, both with groups and one-on-one.
I also have an amateur interest in combinatorial game theory and occasionally update a blog with some basic exposition on the subject (see website).
If you need to contact me, use the e-mail address at this link.
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Nov 18 |
comment |
Cosets and Index In response to a deleted comment, $\left((1,2,4,5)(3,6)\right)^2$ sends $3$ to $6$ and then back to $3$, so it should have $(3)$. Similarly for $(6)$. However, it sends $1$ to $2$ and then to $4$, and $4$ to $5$ and then to $1$, so it should have $(1,4)$ as part of its disjoint cycle decomposition. Similarly, it sends $2$ to $4$ and then to $5$, and $5$ to $1$ and then to $2$, so it should have $(2,5)$. |
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Nov 18 |
comment |
Cosets and Index (2,3) is not in G. (2,3) is in $S_5$ (and I just picked it randomly), and as such, it gives rise to a left coset of G. If I had picked something in G (say, (1,3,4,2,5)) then the left coset (1,3,4,2,5) G would just be G again. It wouldn't be a new coset. |
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Nov 18 |
revised |
Cosets and Index Added a nontrivial coset |
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Nov 18 |
answered | Cosets and Index |
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Nov 17 |
awarded | Autobiographer |
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Nov 17 |
answered | How would you make a (physical) dodecahedron with edges instead of faces? |
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Nov 14 |
revised |
writing a translation and rotation as product of two reflections added l-a tag |
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Nov 14 |
suggested | suggested edit on writing a translation and rotation as product of two reflections |
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Nov 14 |
comment |
writing a translation and rotation as product of two reflections If this is a homework problem, it would help if you would tag it as such. Also, as it's a linear-algebra problem, that tag would be good too. |
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Nov 13 |
revised |
Counting small subsets of a given set Added explicit calculation. |
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Nov 13 |
answered | Counting small subsets of a given set |
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Nov 13 |
comment |
Transferability of space properties via continuous functions Klara, on Stack Exchange, you can also show your appreciation for answers by upvoting them (and eventually accepting them if they end up being a good enough answer for your needs). |
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Nov 13 |
comment |
How to prove this expression? Just like (1+2+4+6)/2=(1/2)+1+2+3 (look at the parentheses), (jl + jmc + lkc + kmc^2) / c=(jl/c)+jm+lk+kmc. Think about what that means about (jl + jmc + lkc + kmc^2) % c. |
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Nov 13 |
comment |
Transferability of space properties via continuous functions Klara, have you written down the definitions of separable(Lindelof) and continuous functions yet? That would be a good start. Also, it might help people find your question if you edit the title to mention either something about separable and/or the fact that it's not properties of "continuous functions" you want to transfer, but rather properties of "spaces" via a continuous function. |
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Nov 13 |
awarded | Revival |
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Nov 13 |
answered | Multinomial Distributions |
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Nov 13 |
comment |
Prove that a function is a total function (as opposed to a partial function) Well, you're probably not expected to worry about formally proving it completely rigorously at this level. But you seemed worried about rigor, so I described what more rigor would be like. If you feel this question is answered you can either accept my answer or add an answer of your own and accept that (since you had an answer first), or I think you can vote to delete your question if you really want. |
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Nov 13 |
comment |
Maximal and Minimal Elements To clarify, the order you're using for your collection is $\subseteq$. And you can know without drawing the diagram by just thinking "which sets contain no proper subsets from the collection", etc. |
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Nov 12 |
answered | Prove that a function is a total function (as opposed to a partial function) |
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Nov 12 |
comment |
Partial Ordering and Covering Relations "there is no transitivity" is a little vague because it's not clear whether you're asking about the binary relation "covers" or the binary relation ≺. I tried to handle both cases in my answer. |