marlu
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 Mar 3 awarded Yearling Jan 19 awarded Guru Dec 8 awarded Nice Answer Nov 25 awarded Enlightened Nov 25 awarded Nice Answer Oct 3 awarded Nice Answer Mar 3 awarded Yearling Feb 11 comment Maximum Modulus Exercise I don't know. One might be able to prove something like that in general, but first one would have to say what exactly is meant by "farthest away from the zeroes". Feb 1 comment Injectivity and localisation in Rings As to why $f: \operatorname{Spec} B \to \operatorname{Spec} A$ is dominant, consider $s \in A$ with $f(\operatorname{Spec} B) \subseteq V(s)$. Then $\varphi(s)$ is contained in every prime ideal of $B$, hence nilpotent in $B$, hence nilpotent in $A$. Jan 14 comment Does commutativity imply Associativity? Well, associativity and commutativity are properties of maps $X\times X \to X$ for a set $X$. In other words, such a map takes two elements as an "input" and returns a single element. In my example, the set under consideration is the set of integers and the map sends each pair of integers $(x,y)$ to $xy+1$. Commutativity means $xy + 1 = yx + 1$ for all $x$ and $y$, which is satisfied. Associativity would mean $x(yz+1) + 1 = (xy+1)z+1$ for all $x$, $y$ and $z$, but it's easy to find examples where this equation does not hold, so the operation is not associative. Dec 16 comment If $F$ is finite over $L_1$ and $L_2$, is it also finite over $L_1 \cap L_2$? I have thought about it, but I couldn't prove it nor find a counterexample. Dec 16 asked If $F$ is finite over $L_1$ and $L_2$, is it also finite over $L_1 \cap L_2$? Sep 30 awarded Explainer Sep 24 awarded Autobiographer Jul 27 awarded Good Answer May 23 comment Finding inverse of polynomial in a field @miloszmaki: Remember that the polynomials have coefficients in $\mathbb F_3$, so that $4 = 1$ and $1/2 = 2$ and $-1 = 2$. Thus the solution you propose is actually the same as mine. Apr 15 answered Isomorphism of intervals of a distributive lattice Mar 3 awarded Yearling Feb 13 awarded Necromancer Jan 17 reviewed Approve The random walk of two drunks