Thomas
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185/100 score
 Apr20 awarded Favorite Question Apr17 reviewed Looks OK In a train of n wagons, at random m passengers enter choosing a wagon.. Apr17 answered Commutative rings and ideals, showing a map is well defined Apr17 revised power series steps help added 7 characters in body Apr17 answered How can I start to learn proof theory? Apr16 reviewed Close Something to the power of infinity is equal to? Apr16 reviewed Close When is a product of [0,1] separable? Apr16 revised Proving $A$ is a subset of $B$ added 21 characters in body Apr16 revised Proving $A$ is a subset of $B$ added 34 characters in body Apr16 comment Prove: The product of any three consecutive integers is divisible by 6. @EthanAlvaree: Consider a list of three consecutive integers: $m$, $m+1$, $m+2$. Now dividing $n$ by $3$ will give you a unique remainder $0\leq r < 3$. That is, $r= 0, 1$, or $2$. Now you can just do the three cases. If $r= 0$, then $n$ is divisible by $3$. If $r=1$, then $n+2$ is divisible by $3$. If $r=2$, then $n+1$ is divisible by $3$. The general case you can do likewise with some type of induction argument on the remainder. Apr11 answered how $1/0.5$ is equal to $2$? Mar28 awarded Good Question Mar6 revised Evaluate $\sum_{n=0}^{N-1} \exp(2 \pi \frac{n}{N} i)$ edited title Mar6 reviewed Close the $\sigma$ algeba generated by the class of open intervals with rational end points coincide with the borel $\sigma$ algebra on the real line. Mar6 reviewed Leave Open Algebraically why is that $\cos(0) =1$? Mar3 awarded Yearling Feb24 answered Simplicity of result of differentiation? Feb23 comment Solving the equation $\sqrt[3]{x^2 + 15} = 2\sqrt[3]{x+1}$ @ANNALIA: I don't understand. This is how you would (could) solve your equation. Feb23 comment Solving the equation $\sqrt[3]{x^2 + 15} = 2\sqrt[3]{x+1}$ @ANNALIA: If you mean if it is necessary to check, then no it is not. Feb23 comment Solving the equation $\sqrt[3]{x^2 + 15} = 2\sqrt[3]{x+1}$ @ANNALIA: What do you mean by a necessity?